下列分布中，从正态分布派生出来的有 未知类型：{'options': ['项分布', '均匀分布[br][/br]', '[tex=1.0x1.214]lLaJjo1WAgOsvIRtwh+bGQ==[/tex]分布', '[tex=0.786x1.286]BlkXDnmzWHxe4M6E9LlofQ==[/tex]分布', '[tex=0.429x0.929]r8lLiDb0KHTzu/2y/Au89w==[/tex]分布'], 'type': 102}

无重水平梁的支承和载荷如图[tex=3.143x1.357]BgQ/JlwKrAD3VnF4spXuAQ==[/tex]所示。已知力[tex=0.786x1.286]BlkXDnmzWHxe4M6E9LlofQ==[/tex]、力偶矩为[tex=1.071x1.286]/vZEgalrrOYkhzS9SMg+fg==[/tex]的力偶和强度为[tex=0.5x1.286]SIrTd7CGXw9GcBP//JIn6w==[/tex]的均布载荷。试求支座[tex=0.786x1.286]pi/GsQ3apuRt43V3XQq/tA==[/tex]和[tex=0.786x1.286]q1djlrfSWHAqH21hBgtrSw==[/tex]处的约束反力。[img=773x226]17d02aa47c0be86.png[/img]

设有连接点[tex=2.857x1.357]YWtkApgNymqGUfnZfMRAzQ==[/tex]和点[tex=2.857x1.357]k1fyl87ihgHd1j9V9uPr9A==[/tex]的一段向上凸的曲线弧[tex=1.571x1.357]iyz0b29FzOWj+O8UfHQWWA==[/tex]，对于曲线弧[tex=1.571x1.357]rW86OGq3hMsl9h7e/G8r9w==[/tex]上任意一 点[tex=2.929x1.357]XSSvH23cbIYXnWROlVlfSQ==[/tex]，曲线弧[tex=1.571x1.357]tD2/O1XfhtRoupoWo8qnHYa4NvYh/wGtk3C3dQ5ObAo=[/tex]与直线段下[tex=1.643x1.286]XlLEr7N9Oo7TQ6z2s+nn8WIlcroIJEExdXdlqzKqO44=[/tex]所围图形的面积为[tex=1.0x1.214]lLaJjo1WAgOsvIRtwh+bGQ==[/tex]，求曲线弧[tex=1.571x1.357]iyz0b29FzOWj+O8UfHQWWA==[/tex]的方程。

for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是：__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1

for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是（）。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1

下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )

请仔细观察下面行列式的计算过程，如果四个等号都理解了，请选择A，否则请选择B。 | a 1 1 1 1 | |a＋4 a＋4 a＋4 a＋4 a＋4| | 1 a 1 1 1 | | 1 a 1 1 1 | | 1 1 a 1 1 |= | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 a | | 1 1 1 1 1 | | 1 a 1 1 1 | =(a＋4) | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 1 | | 0 a–1 0 0 0 | =(a＋4) | 0 0 a–1 0 0 | | 0 0 0 a–1 0 | | 0 0 0 0 a–1 | =(a＋4)(a–1)^4

共有4个站进行码分多址通信。4个站的码片序列为：a：（-1 -1 -1 +1 +1 -1 +1 +1） b：（-1 -1 +1 -1 +1 +1 +1 -1） c：（-1 +1 -1 +1 +1 +1 -1 -1） d：（-1 +1 -1 -1 -1 -1 +1 -1） 现收到这样的码片序列：（-1 +1 -3 +1 -1 -3 +1 +1），则（ ）发送1。

共有四个站进行CDMA通信，现收到这样的码片序列（-3 +1 -1 -1 +1 +1 +1 -3），则下列站点发送了数据1的是（ ） A: （-1 -1 -1 +1 +1 -1 +1 +1） B: （-1 -1 +1 -1 +1 +1 +1 -1） C: （-1 +1 -1 +1 +1 +1 -1 -1） D: （-1 +1 -1 -1 -1 -1 +1 -1）