• 2022-07-26 问题

    [tex=30.429x1.286]y4vlEmFOkH+tzuCDYKlaY/z15ljtnL4GUp5uH1CH4gp201JWiWsafumLadr+7r8DBx7IplJUQObnkmqFnTQVOxZOoyZ2vl0jDFoukPFn8d2PfY5texkkAwzhwJ9Qr+F2YYEt8uNb0+8+XATt+b4dcA==[/tex][tex=19.786x1.286]R8nd+yeHIp3HnSFdLRNOLAGtnDmIMrIOTisSwCCgID2nMZU5kZVf7rzLynEpyecKBVbFOcY9ACn80V2f28sr6EVHLpLDH9VEBTJ86sqNoJY=[/tex]

    [tex=30.429x1.286]y4vlEmFOkH+tzuCDYKlaY/z15ljtnL4GUp5uH1CH4gp201JWiWsafumLadr+7r8DBx7IplJUQObnkmqFnTQVOxZOoyZ2vl0jDFoukPFn8d2PfY5texkkAwzhwJ9Qr+F2YYEt8uNb0+8+XATt+b4dcA==[/tex][tex=19.786x1.286]R8nd+yeHIp3HnSFdLRNOLAGtnDmIMrIOTisSwCCgID2nMZU5kZVf7rzLynEpyecKBVbFOcY9ACn80V2f28sr6EVHLpLDH9VEBTJ86sqNoJY=[/tex]

  • 2022-06-29 问题

    函数\(z = \ln \left( {3x + {y^4}} \right)\)的全微分为 A: \(dz = { { 3 + {y^4}} \over {3x + {y^4}}}dx + { { 3x + 4{y^3}} \over {3x + {y^4}}}dy\) B: \(dz = {3 \over {3x + {y^4}}}dx + { { 4{y^3}} \over {3x + {y^4}}}dy\) C: \(dz = {3 \over {3x + {y^4}}}dy + { { 4{y^3}} \over {3x + {y^4}}}dx\) D: \(dz = {3 \over {3x + {y^4}}}dx - { { 4{y^3}} \over {3x + {y^4}}}dy\)

    函数\(z = \ln \left( {3x + {y^4}} \right)\)的全微分为 A: \(dz = { { 3 + {y^4}} \over {3x + {y^4}}}dx + { { 3x + 4{y^3}} \over {3x + {y^4}}}dy\) B: \(dz = {3 \over {3x + {y^4}}}dx + { { 4{y^3}} \over {3x + {y^4}}}dy\) C: \(dz = {3 \over {3x + {y^4}}}dy + { { 4{y^3}} \over {3x + {y^4}}}dx\) D: \(dz = {3 \over {3x + {y^4}}}dx - { { 4{y^3}} \over {3x + {y^4}}}dy\)

  • 2022-06-11 问题

    假设x=4,y=5,下列哪个逻辑表达式是真的? A: !(x==4)^y!=5 B: x!=4^y==5 C: x==5^y==4 D: x!=5^y!=4

    假设x=4,y=5,下列哪个逻辑表达式是真的? A: !(x==4)^y!=5 B: x!=4^y==5 C: x==5^y==4 D: x!=5^y!=4

  • 2022-05-30 问题

    根据PPT上程序选择正确答案()。 A: x=4,y=5,z=6 B: x=4,y=5,z=4 C: x=4,y=5,z=4 D: x=4,y=4,z=4

    根据PPT上程序选择正确答案()。 A: x=4,y=5,z=6 B: x=4,y=5,z=4 C: x=4,y=5,z=4 D: x=4,y=4,z=4

  • 2022-07-27 问题

    判断年份y是否为闰年的表达式为()。 A: (y%4 == 0) || (y%400 == 0 && y%100 != 0) B: (y%4 == 0 && y%100 != 0) || (y%400 == 0) C: y%4 == 0 && y%100 != 0 D: y%4 == 0

    判断年份y是否为闰年的表达式为()。 A: (y%4 == 0) || (y%400 == 0 && y%100 != 0) B: (y%4 == 0 && y%100 != 0) || (y%400 == 0) C: y%4 == 0 && y%100 != 0 D: y%4 == 0

  • 2022-06-12 问题

    已有定义语句:int x=2,y=4,z=6;if(x>y) z=x;x=y;y=z;执行上述语句后x,y,z的值是____。 A: x=4,y=2,z=2 B: x=4,y=4,z=2 C: x=4,y=6,z=6 D: x=4,y=2,z=6

    已有定义语句:int x=2,y=4,z=6;if(x>y) z=x;x=y;y=z;执行上述语句后x,y,z的值是____。 A: x=4,y=2,z=2 B: x=4,y=4,z=2 C: x=4,y=6,z=6 D: x=4,y=2,z=6

  • 2022-07-26 问题

    假设x=4,y=5,x!=4^y==5

    假设x=4,y=5,x!=4^y==5

  • 2022-06-12 问题

    如下C程序的输出是什么?#include [stdio.h]void Func1 (int x, int y);void Func2 (int *x, int *y); int main() { int x = 3; int y = 4;Func1 (x, y); printf ("x = %d, y = %d\n", x, y);Func2(&x, &y); printf ("x = %d, y = %d\n", x, y);} void Func1 (int x, int y) { x = x + y; y = x - y; x = x - y; printf ("x = %d, y = %d\n", x, y);} void Func2 (int *x, int *y) { *x = *x + *y; *y = *x - *y; *x = *x - *y;;} A: x = 3, y = 4x = 3, y = 4x = 3, y = 4 B: x = 4, y = 3x = 4, y = 3x = 4, y = 3 C: x = 3, y = 4x = 3, y = 4x = 4, y = 3 D: x = 4, y = 3x = 3, y = 4x = 4, y = 3

    如下C程序的输出是什么?#include [stdio.h]void Func1 (int x, int y);void Func2 (int *x, int *y); int main() { int x = 3; int y = 4;Func1 (x, y); printf ("x = %d, y = %d\n", x, y);Func2(&x, &y); printf ("x = %d, y = %d\n", x, y);} void Func1 (int x, int y) { x = x + y; y = x - y; x = x - y; printf ("x = %d, y = %d\n", x, y);} void Func2 (int *x, int *y) { *x = *x + *y; *y = *x - *y; *x = *x - *y;;} A: x = 3, y = 4x = 3, y = 4x = 3, y = 4 B: x = 4, y = 3x = 4, y = 3x = 4, y = 3 C: x = 3, y = 4x = 3, y = 4x = 4, y = 3 D: x = 4, y = 3x = 3, y = 4x = 4, y = 3

  • 2022-07-27 问题

    将一个年份输入y,判断闰年的条件表达式是? A: y%4=0 and y%100!=0 B: y%400=0 C: (y%4=0 and y%100!=0) and (y%400=0) D: (y%4=0 and y%100!=0) or (y%400=0)

    将一个年份输入y,判断闰年的条件表达式是? A: y%4=0 and y%100!=0 B: y%400=0 C: (y%4=0 and y%100!=0) and (y%400=0) D: (y%4=0 and y%100!=0) or (y%400=0)

  • 2022-06-15 问题

    y=arcsin(4x+1)的反函数为 A: y=(sinx-1)/4, x∈R B: y=sin[(x-1)/4], x∈R C: y=sin[(x-1)/4], x∈[-π/2,π/2] D: y=(sinx-1)/4, x∈[-π/2,π/2]

    y=arcsin(4x+1)的反函数为 A: y=(sinx-1)/4, x∈R B: y=sin[(x-1)/4], x∈R C: y=sin[(x-1)/4], x∈[-π/2,π/2] D: y=(sinx-1)/4, x∈[-π/2,π/2]

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