将函数[tex=2.143x0.786]Qx7dC9nSijugfa1AdWsWqg==[/tex]在点[tex=0.857x2.143]QuqdXNVqR1HpaTMNiCIPtw==[/tex]处展开成泰勒级数.

已知一正弦电压的幅值为310V,频率为50Hz,初相为[tex=0.857x2.143]QuqdXNVqR1HpaTMNiCIPtw==[/tex]，写出此正弦电压的时间的数表达式;

四边形ABCD为长方形,AB=2,BC=1,O为AB的中点,在长方形ABCD内随机取一点,取到的点到O的距离小于1的概率为( ) 未知类型：{'options': ['[tex=0.857x2.143]QuqdXNVqR1HpaTMNiCIPtw==[/tex]\xa0\xa0', '[tex=2.286x2.143]ejjfmw5C0f+wXvf+Hdde1A==[/tex]', '[tex=0.857x2.143]lfvByYOa/ce/kg0kkvgfJw==[/tex]', '[tex=2.286x2.143]i6dFV6yfLtLlmdqwsWrQRw==[/tex]'], 'type': 102}

已知一平面经过半径为 [tex=0.786x1.0]as0RCzgUx1oS48cKHRAVVg==[/tex] 的圆柱体的底圆中心, 并且与底面交成 [tex=0.857x2.143]QuqdXNVqR1HpaTMNiCIPtw==[/tex] 角, 计算这个平面截圆柱体所得立体的体积.

四边形[tex=3.071x1.0]RGN59LQ/a5zcnmaK3O1PPA==[/tex]为长方形，[tex=2.786x1.0]xFjVvIZPOoLr39pvP9ZYHg==[/tex]，[tex=2.786x1.0]B1jcAYg5jCmuBn8+vdz6Gg==[/tex]，0为[tex=1.571x1.0]JLMbVw4e37VvhkU494+8Ew==[/tex]的中点，在长方形[tex=3.071x1.0]RGN59LQ/a5zcnmaK3O1PPA==[/tex]内随机取一点，取到的点到0的距离大于1的概率为（）. 未知类型：{'options': ['[tex=0.857x2.143]QuqdXNVqR1HpaTMNiCIPtw==[/tex]', '[tex=2.571x2.143]ejjfmw5C0f+wXvf+Hdde1A==[/tex]', '[tex=0.857x2.143]lfvByYOa/ce/kg0kkvgfJw==[/tex]', '[tex=2.286x2.143]i6dFV6yfLtLlmdqwsWrQRw==[/tex]'], 'type': 102}

for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是：__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1

for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是（）。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1

下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )

请仔细观察下面行列式的计算过程，如果四个等号都理解了，请选择A，否则请选择B。 | a 1 1 1 1 | |a＋4 a＋4 a＋4 a＋4 a＋4| | 1 a 1 1 1 | | 1 a 1 1 1 | | 1 1 a 1 1 |= | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 a | | 1 1 1 1 1 | | 1 a 1 1 1 | =(a＋4) | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 1 | | 0 a–1 0 0 0 | =(a＋4) | 0 0 a–1 0 0 | | 0 0 0 a–1 0 | | 0 0 0 0 a–1 | =(a＋4)(a–1)^4