货币分析法假定货币供给方程是( )。 A: K*P*Y B: m*(D+R) C: m*P*Y D: m*(D+Y)
货币分析法假定货币供给方程是( )。 A: K*P*Y B: m*(D+R) C: m*P*Y D: m*(D+Y)
函数y=x²-1的值域是( ) A: {y|y≥1} B: {y|y≥-1} C: {y|y≤1} D: {y|y≤-1}
函数y=x²-1的值域是( ) A: {y|y≥1} B: {y|y≥-1} C: {y|y≤1} D: {y|y≤-1}
如下C程序的输出是什么?#include [stdio.h]void Func1 (int x, int y);void Func2 (int *x, int *y); int main() { int x = 3; int y = 4;Func1 (x, y); printf ("x = %d, y = %d\n", x, y);Func2(&x, &y); printf ("x = %d, y = %d\n", x, y);} void Func1 (int x, int y) { x = x + y; y = x - y; x = x - y; printf ("x = %d, y = %d\n", x, y);} void Func2 (int *x, int *y) { *x = *x + *y; *y = *x - *y; *x = *x - *y;;} A: x = 3, y = 4x = 3, y = 4x = 3, y = 4 B: x = 4, y = 3x = 4, y = 3x = 4, y = 3 C: x = 3, y = 4x = 3, y = 4x = 4, y = 3 D: x = 4, y = 3x = 3, y = 4x = 4, y = 3
如下C程序的输出是什么?#include [stdio.h]void Func1 (int x, int y);void Func2 (int *x, int *y); int main() { int x = 3; int y = 4;Func1 (x, y); printf ("x = %d, y = %d\n", x, y);Func2(&x, &y); printf ("x = %d, y = %d\n", x, y);} void Func1 (int x, int y) { x = x + y; y = x - y; x = x - y; printf ("x = %d, y = %d\n", x, y);} void Func2 (int *x, int *y) { *x = *x + *y; *y = *x - *y; *x = *x - *y;;} A: x = 3, y = 4x = 3, y = 4x = 3, y = 4 B: x = 4, y = 3x = 4, y = 3x = 4, y = 3 C: x = 3, y = 4x = 3, y = 4x = 4, y = 3 D: x = 4, y = 3x = 3, y = 4x = 4, y = 3
设$E(X),E(Y),D(X),D(Y)$及$cov(X,Y)$均存在,则$D(X-Y)=$ A: $D(X)+D(Y)$ B: $D(X)-D(Y)$ C: $D(X)+D(Y)-2cov(X,Y)$ D: $D(X)+D(Y)+2cov(X,Y)$
设$E(X),E(Y),D(X),D(Y)$及$cov(X,Y)$均存在,则$D(X-Y)=$ A: $D(X)+D(Y)$ B: $D(X)-D(Y)$ C: $D(X)+D(Y)-2cov(X,Y)$ D: $D(X)+D(Y)+2cov(X,Y)$
以下不正确的if语句形式是 。A、if(x>y&&x!=y); B、if(x==y) x+=y;C、if(x!=y) scanf("%d",&x) else scanf("%d",&y); D、if(x<y){x++;y++;} A: if(x>y&&x!=y); B: if(x==y) x+=y; C: if(x!=y) scanf("%d",&x) else scanf("%d",&y); D: if(x<y){x++;y++;}
以下不正确的if语句形式是 。A、if(x>y&&x!=y); B、if(x==y) x+=y;C、if(x!=y) scanf("%d",&x) else scanf("%d",&y); D、if(x<y){x++;y++;} A: if(x>y&&x!=y); B: if(x==y) x+=y; C: if(x!=y) scanf("%d",&x) else scanf("%d",&y); D: if(x<y){x++;y++;}
A.Y=N*YB.Y=N+YC.Y=ND.Y=(N-1)* Y A: Y=N*Y B: Y=N+Y C: Y=N D: Y=(N-1)* Y
A.Y=N*YB.Y=N+YC.Y=ND.Y=(N-1)* Y A: Y=N*Y B: Y=N+Y C: Y=N D: Y=(N-1)* Y
微分方程y"=y’的通解为______ A: y=C1+C2e2x B: y=C1+C2ex C: y=C1+C2x D: y=C1x+C2x2
微分方程y"=y’的通解为______ A: y=C1+C2e2x B: y=C1+C2ex C: y=C1+C2x D: y=C1x+C2x2
微分方程y"=y’的通解为______ A: y=C1+C2e2x B: y=C1+C2ex C: y=C1+C2x D: y=C1x+C2x2
微分方程y"=y’的通解为______ A: y=C1+C2e2x B: y=C1+C2ex C: y=C1+C2x D: y=C1x+C2x2
微分方程y'=y的通解是( ). A: y=x B: y= Cx C: y=eˣ D: y= Ceˣ
微分方程y'=y的通解是( ). A: y=x B: y= Cx C: y=eˣ D: y= Ceˣ
如下程序的输出是什么? #include [stdio.h] void Swap (int x, int y); int main() { int x = 1; int y = 2; printf ("x=%d,y=%d\n", x, y); Swap (x, y); printf ("x=%d,y=%d", x, y); } void Swap (int x, int y) { int temp; temp = x; x = y; y = temp; printf ("x=%d,y=%d\n", x, y); } A: x=1,y=2x=2,y=1x=2,y=1 B: x=1,y=2x=1,y=2x=2,y=1 C: x=1,y=2x=2,y=1x=1,y=2 D: x=1,y=2x=1,y=2x=1,y=2
如下程序的输出是什么? #include [stdio.h] void Swap (int x, int y); int main() { int x = 1; int y = 2; printf ("x=%d,y=%d\n", x, y); Swap (x, y); printf ("x=%d,y=%d", x, y); } void Swap (int x, int y) { int temp; temp = x; x = y; y = temp; printf ("x=%d,y=%d\n", x, y); } A: x=1,y=2x=2,y=1x=2,y=1 B: x=1,y=2x=1,y=2x=2,y=1 C: x=1,y=2x=2,y=1x=1,y=2 D: x=1,y=2x=1,y=2x=1,y=2