• 2022-07-26 问题

    数字口可以输出(),可以输入()。 A: 0(LOW)或1(HIGH);0-1023 B: 0(LOW)或1(HIGH);0.1023 C: 0(LOW)或1(HIGH);0或1 D: 0(LOW)或1(HIGH);0

    数字口可以输出(),可以输入()。 A: 0(LOW)或1(HIGH);0-1023 B: 0(LOW)或1(HIGH);0.1023 C: 0(LOW)或1(HIGH);0或1 D: 0(LOW)或1(HIGH);0

  • 2022-05-27 问题

    If the first high tide takes place at 1:00 A.M., the next high tide will probably take place at ______. A: 7:20 A.M. B: 8:00 A.M. C: 1:45 P.M. D: high noon

    If the first high tide takes place at 1:00 A.M., the next high tide will probably take place at ______. A: 7:20 A.M. B: 8:00 A.M. C: 1:45 P.M. D: high noon

  • 2021-04-14 问题

    代码填空【使用递归实现二分查找】 int binarySearch(int a[], int key, int low, int high) { if (low > high) return -1; int mid; mid = (low + high) / 2; if (key == a[mid]) return mid; else if (key < a[mid]) return ________(1)__________; else return ________(2)______________; }

    代码填空【使用递归实现二分查找】 int binarySearch(int a[], int key, int low, int high) { if (low > high) return -1; int mid; mid = (low + high) / 2; if (key == a[mid]) return mid; else if (key < a[mid]) return ________(1)__________; else return ________(2)______________; }

  • 2021-04-14 问题

    1、The regularity of China’s topographical distribution is high in the east and low in the west.

    1、The regularity of China’s topographical distribution is high in the east and low in the west.

  • 2022-05-28 问题

    对于折半查找插入排序的最后一轮开始之前,如果关键字序列是:2,3,4,8,9,7,分别存在R&#91;1~6&#93;中,请计算:对于关键字7,先进行折半查找后,high=_____1_______,7的插入位置应为:________2_______(写值) 对于折半查找插入排序的最后一轮开始之前,如果关键字序列是:2,3,6,8,9,5,分别存在R&#91;1~6&#93;中,请计算:对于关键字5,先进行折半查找后,high=_____3_______,5的插入位置应为:________4_______(写值)通过上述1和2,可以判断:折半查找后,当前关键值的插入位置应该是high+1,请问上述说法是否正确:________5______(填:对/错)

    对于折半查找插入排序的最后一轮开始之前,如果关键字序列是:2,3,4,8,9,7,分别存在R&#91;1~6&#93;中,请计算:对于关键字7,先进行折半查找后,high=_____1_______,7的插入位置应为:________2_______(写值) 对于折半查找插入排序的最后一轮开始之前,如果关键字序列是:2,3,6,8,9,5,分别存在R&#91;1~6&#93;中,请计算:对于关键字5,先进行折半查找后,high=_____3_______,5的插入位置应为:________4_______(写值)通过上述1和2,可以判断:折半查找后,当前关键值的插入位置应该是high+1,请问上述说法是否正确:________5______(填:对/错)

  • 2022-06-14 问题

    —“Is shopping there expensive?” A: so high to B: as high to C: so high as D: as high as

    —“Is shopping there expensive?” A: so high to B: as high to C: so high as D: as high as

  • 2022-06-17 问题

    Questions 1 and 2 will be based on the following news item. A: The reason behind the low high school graduation rate. B: The best time to help students graduate from high school. C: An organization which helps students graduate from high school. D: The number of students who graduate from high school.

    Questions 1 and 2 will be based on the following news item. A: The reason behind the low high school graduation rate. B: The best time to help students graduate from high school. C: An organization which helps students graduate from high school. D: The number of students who graduate from high school.

  • 2022-06-15 问题

    This statue stands just ______ as that one. A: the same high B: so high C: as high D: high

    This statue stands just ______ as that one. A: the same high B: so high C: as high D: high

  • 2021-04-14 问题

    (1 )College is more expensive than high school because of tuition, living expenses, and books.

    (1 )College is more expensive than high school because of tuition, living expenses, and books.

  • 2021-04-14 问题

    题目:计算并输出high以内最大的10个素数之和,high由主函数传 给fun函数,若high的值为100,则函数的值为732。 #include "stdio.h" int fun( int high ) { int sum = 0, n=0, j, yes; /***********SPACE***********/ while ((high >= 2) && (【?】)) { yes = 1; for (j=2; j<=high/2; j++ ) /***********SPACE***********/ if (【?】) { yes=0; break; } if (yes) { sum +=high; n++; } high--; } /***********SPACE***********/ 【?】; } main { printf("%d ", fun (100)); }

    题目:计算并输出high以内最大的10个素数之和,high由主函数传 给fun函数,若high的值为100,则函数的值为732。 #include "stdio.h" int fun( int high ) { int sum = 0, n=0, j, yes; /***********SPACE***********/ while ((high >= 2) && (【?】)) { yes = 1; for (j=2; j<=high/2; j++ ) /***********SPACE***********/ if (【?】) { yes=0; break; } if (yes) { sum +=high; n++; } high--; } /***********SPACE***********/ 【?】; } main { printf("%d ", fun (100)); }

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