压力容器设计中两种不同的设计方法分别是1.____________；2.___________；

滑动窗（截短）译码回溯算法的三个基本操作1.____________

容器的超压爆破分为四个阶段，它们分别是1.____________；2.____________；3.______________；4._________________。

采访中有许多素材是____，比如文件、报纸、照片等理性素材或者形象素材。记者要充分调动各种形象手段营造动态的氛围，把这类建立在空间延展基础上的素材变为按时间发展的电视素材。具体方法包括：1.____________；2.____________。

1．____________年,____________规律的重新发现,标志着遗传学学科的建立.在遗传学的发展史上,许多科学家由于其突出的学术贡献,先后获得了诺贝尔奖金,____________因为他用____________作为实验材料,创立了基因理论,证明基因位于染色体上,而成为第一个因在遗传学领域的突出贡献获得诺贝尔奖金的科学家.

for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是：__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1

Banker: First Venture Bank. How may I help you? Accountant: Hi. This is Wendy from Capital Incorporated. I just received an 1．____________ ____________ from you. Banker: I can help you with that. What is your 2. _________ _________ ? Accountant: It’s 58756. We have a second account with you 3． ____________ ____________ . Banker: Let me see ... Your company’s other account has a balance of $1000.00. Accountant: Good. Can I 4. ____________ $500 into the overdrawn account? Banker: 5 .____________ . Is there anything else I can help you with today? Accountant: No, 6. ____________ ____________ . Thanks.

for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是（）。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1

下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )