8. 下列不等式正确的是 A: $0\lt \int_{0}^{\frac{\pi }{2}}{\sin (\sin x)dx}\lt \int_{0}^{\frac{\pi }{2}}{\cos (\sin x)dx}$ B: $0\lt \int_{0}^{\frac{\pi }{2}}{\cos (\sin x)dx}\lt \int_{0}^{\frac{\pi }{2}}{\sin (\sin x)dx}$ C: $\int_{0}^{\frac{\pi }{2}}{\sin (\sin x)dx}\lt 0\lt \int_{0}^{\frac{\pi }{2}}{\cos (\sin x)dx}$ D: $\int_{0}^{\frac{\pi }{2}}{\cos (\sin x)dx}\lt 0\lt \int_{0}^{\frac{\pi }{2}}{\sin (\sin x)dx}$

求方程 的根的程序( )。 A: A.solve(sin(x)-2*x+0.5=0,x); B: B.solve(sin(x)-2*x+0.5=0,'x'); C: C.solve('sin(x)-2*x+0.5=0','x'); D: D.solve('sin(x)-2*x+0.5=0',x);

3.11 在纯电感电路中，若u＝UmsinωtV，则i为（）。 A: i＝(Um／ωL)sin(ωt＋π／2)A B: i＝Umωsin(ωt－π／2)A C: i＝(Um／ωL)sin(ωt-π／2)A D: i＝Umωsin(ωt+π／2)A

∫(上限л/2下限0)sin^2（x/2）dx

函数[img=79x27]180355ae2690a03.png[/img]在x=2处的二阶泰勒展开式为 A: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)+exp(sin(2))*(sin(2)/2-cos(2)^2/2)*(x-2)^2 B: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)-exp(sin(2))*(sin(2)/2-cos(2)^2/2)*(x-2)^2 C: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)-exp(sin(2))*(sin(2)/2+cos(2)^2/2)*(x-2)^2 D: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)+exp(sin(2))*(sin(2)/2+cos(2)^2/2)*(x-2)^2

\( \lim \limits_{x \to 0} { { \sqrt {1 + x\sin x} - \cos x} \over { { {\sin }^2}{x \over 2}}} = \)______ 。

设tanα=1,且cosα<0,则sinα=() A: -√2/2 B: -1/2 C: 1/2 D: √2/2

sin(nx)^2*cos(x)^2从0到π的积分是多少

&#91;x^2*sin(1/x^2)&#93;/x的X趋于0的极限,为什么不能用sin(1/x^2)~1/x^2带入.

MATLAB中，A=[0:0.5:2]*pi,那么sin(A)= [0 1 0 -1 0]。