• 2022-11-04 问题

    6.7fcntl函数的原型函数为说明 A: intfcntl(constchar*pathname,flags,intperms) B: intfcntl(intfd,intcmd,structflock*lock) C: FILE*fcntl(constchar*path,constchar*mode) D: intfcntl(intnumfds,fd_set*readfds,fd_set*writefds,fd_set*exeptfds,structtimeval*timeout)

    6.7fcntl函数的原型函数为说明 A: intfcntl(constchar*pathname,flags,intperms) B: intfcntl(intfd,intcmd,structflock*lock) C: FILE*fcntl(constchar*path,constchar*mode) D: intfcntl(intnumfds,fd_set*readfds,fd_set*writefds,fd_set*exeptfds,structtimeval*timeout)

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