y=x/(1-x2)的微分为(1-x2)/(1-x2)2dx
举一反三
- 若∫f(x)dx=x2+c,则∫xf(1-x2)dx=( ). A: 2(1-x2)2+c B: -2(1-x2)2+c C: -1/2(1-x 2 ) 2 +C D: 1/2(1-x 2 ) 2 +C
- 若∫f(x)dx=x+C,则∫xf(1-x2)dx=______ A: 2(1-x2)+C B: -2(1-x2)+C C: -1/2(1-x 2 ) 2 +C D: 1/2(1-x 2 ) 2 +C
- y=x/(1-x2)的微分为(1-x2)/(1-x2)2dx
- y=x/(1-x2)的微分为(1-x2)/(1-x2)2dx。()
- y=x/(1-x2)的微分为(1-x2)/(1-x2)2dx。()