defremove_key(d,key):r=dict(d)delr[key]returnrx={1:2,3:4,4:3,2:1,0:0}print(remove_key(x,1))
举一反三
- How many key comparisons are needed in searching for key value 38（） A: 1 B: 2 C: 3 D: 4
- D = {'苹果': 4, '梨': 5, '榴莲': 1} D2 = {'香蕉': 3, '柠檬': 3, '凤梨':2 , '苹果':3} for key in D: for key2 in D2: if key == key2: print(D[key]+D2[key2]) 以上代码运行结果为（ ）? A: 10 B: 5 C: 7 D: 21
- a = [x for x in range(4) if x % 2 ==1]，语句print(a)输出为 A: [1, 2, 3] B: [0, 1, 2, 3] C: [0, 2] D: [1, 3]
- Four keys to getting hired are begun in different ways stylistically. Key 1 starts with a ____.Key 2 starts with a ___. Key 3 starts with a ____. Key4 starts with a ____.
- 已知列表对象x = ['11', '2', '3','1']，那么表达式 max(x,key=len) 的值为（ ）。A. B. C.D. A: '11' B: '1' C: '2' D: '3'