若函数$f(x)$具有二阶导数,且$y=f({{x}^{2}})$,则$y'' =$( )。
A: $f'' ({{x}^{2}})$
B: $2f'’ ({{x}^{2}})$
C: $2f’ ({{x}^{2}})+4{{x}^{2}}f’' ({{x}^{2}})$
D: $4{{x}^{2}}f’ ({{x}^{2}})+2f'' ({{x}^{2}})$
A: $f'' ({{x}^{2}})$
B: $2f'’ ({{x}^{2}})$
C: $2f’ ({{x}^{2}})+4{{x}^{2}}f’' ({{x}^{2}})$
D: $4{{x}^{2}}f’ ({{x}^{2}})+2f'' ({{x}^{2}})$
举一反三
- 已知\( y = {f^2}(x) \),假设\( f(u) \)二阶可导,则 \( y'' \)为( ). A: \( 2{[f'(x)]^2} + 2f(x)f'(x) \) B: \( 2[f'(x)] + 2f(x)f''(x) \) C: \( 2{[f'(x)]^2} + 2f(x)f''(x) \) D: \( 2{[f'(x)]^2} + f(x)f''(x) \)
- 已知\( y = f({x^2}) \),假设\( f(u) \)二阶可导,则\( y'' \)为( ). A: \( 4{x^2}f''({x^2}){\rm{ + }}2f'({x^2}) \) B: \( {x^2}f''({x^2}){\rm{ + }}2f'({x^2}) \) C: \( 4{x^2}f''({x^2}){\rm{ + }}f'({x^2}) \) D: \( {x^2}f''({x^2}){\rm{ + }}f'({x^2}) \)
- 【单选题】对任意实数x 1 , y 1 , x 2 , y 2 , x 1 < x 2 , y 1 < y 2 , 分布函数P{x 1 <X≤x 2 , y 1 <Y≤y 2 }=? A. F(x 2 , y 2 )+ F(x 1 , y 1 )+ F(x 1 , y 2 )+ F(x 2 , y 1 ) B. F(x 2 , y 2 )- F(x 1 , y 1 )+ F(x 1 , y 2 )- F(x 2 , y 1 ) C. F(x 2 , y 2 )+ F(x 1 , y 1 )- F(x 1 , y 2 )- F(x 2 , y 1 ) D. F(x 2 , y 2 )- F(x 1 , y 1 )- F(x 1 , y 2 )+ F(x 2 , y 1 )
- 若f″(x)存在,则函数y=ln[f(x)]的二阶导数为:() A: (f″(x)f(x)-[f′(x)]<sup>2</sup>)/[f(x)]<sup>2</sup> B: f″(x)/f′(x) C: (f″(x)f(x)+[f′(x)]<sup>2</sup>)/[f(x)]<sup>2</sup> D: ln″[f(x)]·f″(x)
- 设f(x)为连续函数,F(t)=f(x)dx,则F’(2)=()。 A: 2f(2) B: f(2) C: -f(2) D: 0