求极限lim(n→∞)tan^n(π/4+2/n)
解lim(n→∞)tan^n(π/4+2/n)=lim(n→∞)[(tan(π/4)+tan(2/n))/(1-tan(π/4)tan(2/n))]^n(着一步就是tan(A+B)拆分的公式啊~=lim(n→∞)[(1+tan(2/n))/(1-tan(2/n))]^n(着一步就是求出tan(π/4)=1啊哪里看不明白再追问
举一反三
内容
- 0
求极限1:lim(n→∞)4根号n/[根号(n+9)-根号(n+8)]
- 1
求极限:lim(1-x)tanΠ/2
- 2
lim(1/n的三次方+1)+(4/n的三次方+2)一直到+n的平方/n的三次方+n的极限
- 3
计算下列极限lim(n→∞)(1/n)*(n!)^1/n
- 4
lim(n→无穷){n/(√n^2+1)+(√n^2-1)}的极限