• 2022-06-10
    本题建立交对并运算的分配律。令[tex=0.929x1.0]FV0k2T/xaj6dPCbFnkB3/g==[/tex]、[tex=0.929x1.0]ep004cu6Ev4qhlMpamsNGg==[/tex]和[tex=0.857x1.0]oXAqKViyEOXeAjRP4JQG3g==[/tex]为[tex=2.714x1.071]319e/AVA5VexfWBQXpJ9ug==[/tex]阶0-1矩阵。证明[tex=13.786x1.357]qTT9ohZSoF+wT3IvQFgnLJslErFTSqvEJjJTW2B2HEpAx7HErAirvAM3rhMHCIlvHd5nMfpAVaW5CTuA8fI9gJ2j4N/ynM8KP3/cnuY03/Al9tNqNolMCpHGu4kjGPiqpNouL5aNHUMbvsXhS6Gv5w+Cgxi+WMaNkRd+zRKIFtluXVwphqpr2Ld/1SLQvC3F[/tex]
  • 举一反三