一绝热容器被隔板分成体积相等的两部分, 左边有 [tex=4.286x1.071]SnkKD2y4MBNo9JVvo9DBH/tnOBWvHFG5FShqOgm0TmVAoHhIzdy4Gw/3v2S7KY0S[/tex]的[tex=1.143x1.214]FrpCv2pDZj1w9pLp9Lnbxx0hqwWFA3rgq3BQdzTyonM=[/tex], 右边有[tex=4.286x1.071]SnkKD2y4MBNo9JVvo9DBHzW60eBxSZ7NCAT641RvH4xPZm1KlWHW5LaYgGTDNt2z[/tex]的 [tex=1.143x1.214]PiRLIghOIvGV4KOsB9WBPqq89AZcc0OSNXifi7n1cnk=[/tex]。设两种气体均可当作理想气体, [tex=5.143x2.357]YZldo5gzSfez/CavKLUmL/smv+ABLFlWcXAOkUcPyBek/ZyYsIvgMeIYxE4TnuS2[/tex]。求两边温度相等时总的熵变。若将隔板抽去, 求总的熵变。
解：两边温度相等后, [tex=2.071x1.214]IZOo1mJim81aWdEkXhsxsw==[/tex], [tex=25.071x2.786]j5GKmruk37g5mw2scTL5paYAuyKgFrFKnjMQGX0lQvIFYKw8IaDO9ckZxA7ktrBYlF0m6WNBENCra2y43/etAj12Lvb3aMi1i28Sw2T6KeMAGjnvsivXStkupcN/21M9PmgyVDOOaCEascCyRH22qixx8Vtj3gGoYix5u0tv/MSqPBoBUkfSnXrnR3ZkBHTr1HveS6Alz9Qjns5L44hzkAfLw1f98I9WLcAmgW+Y6sG22D4f6YQE+Q3d7FjpSHZN[/tex][tex=31.857x7.857]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[/tex][tex=6.071x1.214]KTAuU81wVwYQriT2OZ6cVYKnn2NAPbdAjRvW9xv58Ke89dtMM8Wv+eTCJrTs86ql[/tex]抽去隔板后，两气体在恒温下混合，每一种气体的分压均变为原来压力的一半[tex=28.286x3.071]qeiYnKXLEhyhuGRg8yLtr2XG+c4+57Gb7n8GCdDWu1rWZl3joeqi+QR8gX1d9Ti2Sf+F5IIQdSemTqhRzo8XjAFGCWgIv+AbPMoTLDuac08ytLp2x1N3kKtzXcU+KgRYgaiC0eqF5bCy/0NaTC8vIw/kbMGRkFt5GtreluDQfz4svMjlzt+7jb0l0UONwHUR5F1YkNRXxPT06qqE6xo9kFI49DewUTUWwOAEQ/wYeoi1uSldWW1i2O07rurPtcVcUlBPLuWlwx5AjoR3bBMoMJipxVmPUsY10koDZIz8jSE=[/tex]故总的熵变为[tex=14.5x1.5]TDRcH8StEF3lLJiL/tM4c+cTWQLS7JkGPg+Q4aQkMRfJBu84r2N9Z1Ec5qMGfPzDlfAwZgZhUamlQSeB6MQY7ofpXusYYA0S2kjewJU8I9aEl9F5iGcLS9pQNpnPDsk7[/tex]
举一反三
- 一绝热容器被隔板分成体积相等的两部分,左边有[tex=4.643x1.071]e9FVIHdoHasGi/DgoNLodIvXbRhUAefYcdtdcueV+Sw=[/tex]的[tex=1.143x1.214]8xlhAzOvvRWjDpnFPOR64g==[/tex],右边有[tex=4.643x1.071]AaXOIsf9DESZV/PM4gUSrnjcC69nxXZ3CM7XcOWNfUU=[/tex]的[tex=1.214x1.214]sU9dEKNtUiirIgTUffTS6A==[/tex]。设两种气体均可当作理想气体,[tex=5.786x1.571]CHkD8DWmkmhZbCBN8EzTh7nF0Ft4eHNuwn3zyBwKcW8=[/tex]。求通过隔板传热使两边温度相等时总的熵变。若将隔板抽去,求总的熵变。
- 【单选题】Which of the following matrices does not have the same determinant of matrix B: [1, 3, 0, 2; -2, -5, 7, 4; 3, 5, 2, 1; -1, 0, -9,-5] A. [1, 3, 0, 2; -2, -5, 7, 4; 0, 0, 0, 0; -1, 0, -9, -5] B. [1, 3, 0, 2; -2, -5, 7, 4; 1, 0, 9, 5; -1, 0, -9, -5] C. [1, 3, 0, 2; -2, -5, 7, 4; 3, 5, 2, 1; -3, -5, -2, -1] D. [1, 3, 0, 2; -2, -5, 7, 4; 0, 0, 0, 1; -1, 0, -9, -5]
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- 有代码片段：function f(y) {var x=y*y;return x;} for(var x=0;x< 5;x++) {y=f(x);document.writeln(y);}输出结果是( )。 A: 0 1 2 3 4 B: 0 1 4 9 16 C: 0 1 4 9 16 25 D: 0 1 2 3 4 5
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
内容
- 0
set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
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下列哪条语句是正确的（ ） A: A=[1 2;3 4];B=[3;7];A.*B; B: A=cell(2,3);A(1,2)=[4;5]; C: A=[2 3 5 7;9 4 6 1;7 3 2 5];B=[1 7;0 5];A(2:end,2:2:end) D: x=-5:5;y=-5:5;z=x.*x-y.*y;surf(x,y,z);
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list(map(lambda x, y: x+y, range(5), range(5, 10)))运行结果正确的是( )。 A: ['5', '7', '9', '11', '13'] B: [5, 7, 9, 11, 13] C: ['0', '1', '2', '3', '4'] D: [0, 1, 2, 3, 4]
- 3
以下程序段实现的输出是（）。for(i=0;i<;=9;i++)s[i]=i;for(i=9;i>;=0;i--)printf("%2d",s[i]);[/i][/i] A: 9 7 5 3 1 B: 1 3 5 7 9 C: 9 8 7 6 5 4 3 2 1 0 D: 0 1 2 3 4 5 6 7 8 9
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双曲线x^2/16-y^2/9=1的渐近线方程为() A: y=±16x/9 B: y=±9x/16 C: x/3±y/4=0 D: x/4±y/3=0