A: $cos\alpha=3/\sqrt{14},cos\beta=-1/\sqrt{14},cos\gamma=3/\sqrt{14}$
B: $cos\alpha=4/\sqrt{14},cos\beta=-1/\sqrt{14},cos\gamma=3/\sqrt{14}$
C: $cos\alpha=2/\sqrt{14},cos\beta=-1/\sqrt{14},cos\gamma=3/\sqrt{14}$
D: $cos\alpha=3/\sqrt{14},cos\beta=9/\sqrt{14},cos\gamma=3/\sqrt{14}$
举一反三
- 以\( (2,2,1) \)为起点，以\( (1,3,0) \)为终点的向量的方向余弦为（ ）. A: \( \cos \alpha = { { - 1} \over {\sqrt 3 }},\cos \beta = {1 \over {\sqrt 3 }},\cos \gamma = { { - 1} \over {\sqrt 3 }} \) B: \( \cos \alpha = {1 \over {\sqrt 3 }},\cos \beta = { { - 1} \over {\sqrt 3 }},\cos \gamma = { { - 1} \over {\sqrt 3 }} \) C: \( \cos \alpha = { { - 1} \over {\sqrt 3 }},\cos \beta = { { - 1} \over {\sqrt 3 }},\cos \gamma = { { - 1} \over {\sqrt 3 }} \) D: \( \cos \alpha = { { - 1} \over {\sqrt 3 }},\cos \beta = { { - 1} \over {\sqrt 3 }},\cos \gamma = {1 \over {\sqrt 3 }} \)
- \((\cos\alpha \cos\beta, \cos\alpha \sin\beta, \sin\alpha),(1,1,0),(1,2,1)\)张成六面体体积最大为___. A: \(\sqrt{3}\) B: \(2\sqrt{3}\) C: \(\sqrt{6}\)
- 计算[img=127x40]1803177bfc8c3e2.png[/img]的程序表达为 A: sqrt(sin alpha ^ 2 + cos beta ^ 2) B: sqrt(sin^2(alpha) + cos^2(beta)) C: sqrt(pow(sin(alpha), 2) + pow(cos(beta), 2)) D: sqrt pow(sin(alpha), 2) + pow(cos(beta), 2)
- 14、求平方根函数的函数名为（ ）。 A: cos B: abs C: pow D: sqrt
- 曲线$\left\{ \matrix{ {x^2} + {y^2} + {z^2} = 9 \cr y = x \cr} \right.$的参数方程为( ). A: $$\left\{ \matrix{ x = \sqrt 3 \cos t \cr y = \sqrt 3 \cos t \cr z = \sqrt 3 \sin t \cr} \right.(0 \le t \le 2\pi )$$ B: $$\left\{ \matrix{ x = {3 \over {\sqrt 2 }}\cos t\cr y = {3 \over {\sqrt 2 }}\cos t \cr z = 3\sin t \cr} \right.(0 \le t \le 2\pi )$$ C: $$\left\{ \matrix{ x = \cos t\cr y = \cos t\cr z = \sin t \cr} \right.(0 \le t \le 2\pi )$$ D: $$\left\{ \matrix{ x = {{\sqrt 3 } \over 3}\cos t\cr y = {{\sqrt 3 } \over 3}\cos t \cr z = {{\sqrt 3 } \over 3}\sin t\cr} \right.(0 \le t \le 2\pi )$$
内容
- 0
\(\int{\sin 3x\cos 4xdx}\)=( )。 A: \(\frac{1}{2}\sin x-\frac{1}{14}\cos 7x+C\) B: \(\frac{1}{2}\cos x-\frac{1}{14}\cos 7x+C\) C: \(\frac{1}{2}\cos x+\frac{1}{14}\sin 7x+C\) D: \(\frac{1}{2}\sin x+\frac{1}{14}\sin 7x+C\)
- 1
函数$f(x,y)=\sqrt{1+{{y}^{2}}}\cos x$在点$(0,1)$处的1次Taylor多项式为 A: $\sqrt{2}-\frac{1}{\sqrt{2}}(y-1)$ B: $\frac{\sqrt{2}}{2}+\frac{1}{\sqrt{2}(}y-1)$ C: $2\sqrt{2}+\frac{1}{\sqrt{2}}(y-1)$ D: $\sqrt{2}+\frac{1}{\sqrt{2}}(y-1)$
- 2
以下表达式中，有两个的计算结果是相同的，请挑选出来 A: 1 / sqrt(sin(x) * sin(x) + cos(y) * cos(y)) B: sqrt(pow(sin(x), 2) + pow(cos(y), 2)) C: pow(sin(x) * sin(x) + cos(y) * cos(y), 0.5) D: pow(pow(sin(x), 2) + pow(cos(y), 2), 2)
- 3
设$L$是平面$x\cos\alpha+y\cos\beta+z\cos\gamma=1$上的闭曲线, 它所包围的区域面积为$S$, 则曲线积分$$\oint_L (z\cos\beta-y\cos\gamma)dx+(x\cos\gamma-z\cos\alpha)dy+(y\cos\alpha-x\cos\beta)dz=S,$$其中$L$依正向进行。
- 4
求平方根函数是（） A: Abs() B: Cos() C: Sqrt() D: ToString()