• 2022-06-29
    求下列函数的拉普拉斯变换.[tex=9.143x1.357]uyYSU1nVl8sw8F0zwZKZX9gvC8c4P2XVGPLjxfw0bCw=[/tex].
  • [tex=25.214x1.357]YOoYLHKWy9CxjYqSPxWpnNw70XJF99mqPg8oI62vh4oJOYaaYtN0IoLRPtwtg6gTzkEbcM3yadQd41oKK4B52HEzoIIHcv7MioxOJAikZk0=[/tex][tex=12.357x2.429]VAQg48+wr0ogRqQTh4VoDKR1MOF1JdyhSmt+JHskJNaydheF/eYI8UoTJOLVilooZO/wsYugRzYPwTbnEH0rzYM0rFGSj+q9/Ji6xL1cNyA=[/tex].

    内容

    • 0

      set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为? A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}

    • 1

      已知函数f(x)=ax+a-x(a>0且a≠1),且f(1)=3,则f(0)+f(2)的值是(  ) A: 7 B: 8 C: 9 D: 10

    • 2

      设随机变量(X,Y)的联合密度函数为p(x,y)=k(6-x-y),0 (1) 1/8 (2) 3/8

    • 3

      list(range(-1,10,2)) A: [0, 2, 4, 6, 8, 10] B: [-1, 1, 3, 5, 7, 9] C: [0, 2, 4, 6, 8]

    • 4

      【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=