• 2022-06-05
    设=cos4x,则dy=
    A: 4sin4xdx
    B: -4sin4xdx
    C: (1/4)sin4xdx
    D: -(1/4)sin4xdx
  • B

    内容

    • 0

      sinα-cosα=m求sin^4α+cos^4α的值

    • 1

      求微分方程[img=143x21]17da5f14490e50e.png[/img]的通解,实验命令为(). A: dsolve(D2y-2*Dy+5*y=sin(2*x),x)ans =exp(x)*sin(2*x)*C2+exp(x)*cos(2*x)*C1+1/17*sin(2*x)+4/17*cos(2*x) B: dsolve('D2y-2*Dy+5*y=sin(2*x)','x')ans =cos(2*x)*(sin(4*x)/17 - cos(4*x)/68 + 1/4) - sin(2*x)*(cos(4*x)/17 + sin(4*x)/68) + C1*cos(2*x)*exp(x) - C2*sin(2*x)*exp(x) C: dsolve(D2y-2*Dy+5*y=sin(2*x),'x','y')ans =exp(x)*sin(2*x)*C2+exp(x)*cos(2*x)*C1+1/17*sin(2*x)+4/17*cos(2*x)

    • 2

      函数\(y = \cos (4 - 3x)\)的导数为( ). A: \( - 3\sin \left( {4 - 3x} \right)\) B: \(3\sin \left( {4 - 3x} \right)\) C: \(3\sin \left( {4 + 3x} \right)\) D: \( - 3\sin \left( {4 + 3x} \right)\)

    • 3

      求微分方程[img=364x55]17da65386dfd612.png[/img]的通解; ( ) A: - cos(2*x)*exp(x)*(x/4 - sin(4*x)/16) + C23*cos(2*x)*exp(x) + C24*sin(2*x)*exp(x) B: (3*sin(2*x)*exp(x))/32 - (sin(6*x)*exp(x))/32 - cos(2*x)*exp(x)*(x/4 - sin(4*x)/16) + C23*cos(2*x)*exp(x) + C24*sin(2*x)*exp(x) C: - sin(4*x)/16) + C23*cos(2*x)*exp(x) + C24*sin(2*x)*exp(x) D: (sin(6*x)*exp(x))/32 - cos(2*x)*exp(x)*(x/4 - sin(4*x)/16) + C23*cos(2*x)*exp(x) + C24*sin(2*x)*exp(x)

    • 4

      积分$\int_0^1 x \arctan xdx=$()。 A: $\frac{\pi}{4}+\frac{1}{2}$ B: $\frac{\pi}{4}$ C: $\frac{\pi}{4}-\frac{1}{2}$ D: $\frac{1}{2}$