A: 4sin4xdx
B: -4sin4xdx
C: (1/4)sin4xdx
D: -(1/4)sin4xdx
举一反三
- 已知\( y = \cos x \),则\( dy \)为( ). A: \( \cos x \) B: \( {\rm{ - }}\sin x \) C: \( \cos xdx \) D: \( {\rm{ - }}\sin xdx \)
- 已知\( y = \tan x \),则\( dy \)为( ). A: \( \tan xdx \) B: \( \cos xdx \) C: \( {\sec ^2}xdx \) D: \( \sin xdx \)
- $\int \sin^3 x \cos x dx = $ A: $\frac{\sin^4 x}{4} +C$ B: ${\sin^4 x} +C$ C: $\frac{\cos^4 x}{4} +C$ D: $\frac{\cos^4 x}{4} +C$
- 设$\int_0^\pi {[f(x) + f''(x)]\sin xdx = 5} $,$f(\pi ) = 2$,求$f(0)$=( ) A: 1 B: 2 C: 3 D: 4
- 下列计算正确的是() A: log2cos7π4=-12 B: 若f(cos x)=cos 2x,则f(sin 30°)=12 C: 若sin(π+α)=-12,则sin(4π-α)=-12 D: 设tan(π+α)=2,则sin(α-π)+cos(π-α)sin(π+α)-cos(π-α)=1
内容
- 0
sinα-cosα=m求sin^4α+cos^4α的值
- 1
求微分方程[img=143x21]17da5f14490e50e.png[/img]的通解,实验命令为(). A: dsolve(D2y-2*Dy+5*y=sin(2*x),x)ans =exp(x)*sin(2*x)*C2+exp(x)*cos(2*x)*C1+1/17*sin(2*x)+4/17*cos(2*x) B: dsolve('D2y-2*Dy+5*y=sin(2*x)','x')ans =cos(2*x)*(sin(4*x)/17 - cos(4*x)/68 + 1/4) - sin(2*x)*(cos(4*x)/17 + sin(4*x)/68) + C1*cos(2*x)*exp(x) - C2*sin(2*x)*exp(x) C: dsolve(D2y-2*Dy+5*y=sin(2*x),'x','y')ans =exp(x)*sin(2*x)*C2+exp(x)*cos(2*x)*C1+1/17*sin(2*x)+4/17*cos(2*x)
- 2
函数\(y = \cos (4 - 3x)\)的导数为( ). A: \( - 3\sin \left( {4 - 3x} \right)\) B: \(3\sin \left( {4 - 3x} \right)\) C: \(3\sin \left( {4 + 3x} \right)\) D: \( - 3\sin \left( {4 + 3x} \right)\)
- 3
求微分方程[img=364x55]17da65386dfd612.png[/img]的通解; ( ) A: - cos(2*x)*exp(x)*(x/4 - sin(4*x)/16) + C23*cos(2*x)*exp(x) + C24*sin(2*x)*exp(x) B: (3*sin(2*x)*exp(x))/32 - (sin(6*x)*exp(x))/32 - cos(2*x)*exp(x)*(x/4 - sin(4*x)/16) + C23*cos(2*x)*exp(x) + C24*sin(2*x)*exp(x) C: - sin(4*x)/16) + C23*cos(2*x)*exp(x) + C24*sin(2*x)*exp(x) D: (sin(6*x)*exp(x))/32 - cos(2*x)*exp(x)*(x/4 - sin(4*x)/16) + C23*cos(2*x)*exp(x) + C24*sin(2*x)*exp(x)
- 4
积分$\int_0^1 x \arctan xdx=$()。 A: $\frac{\pi}{4}+\frac{1}{2}$ B: $\frac{\pi}{4}$ C: $\frac{\pi}{4}-\frac{1}{2}$ D: $\frac{1}{2}$