• 2022-06-19
    设(1[tex=2.143x1.357]ZeFHV7/B9tbWRcAnHTJTkw==[/tex]在点[tex=0.857x1.0]KInWOYOIU+u9wjpJut/pOQ==[/tex]解析,[tex=4.286x1.357]+uO54rrM54jdyvvqepiorXp6khglXMdiTzkQVrsIEos=[/tex];(2)[tex=3.643x1.357]XlKeY9cidN1P+CLNhKp4hg==[/tex]以[tex=0.857x1.0]KInWOYOIU+u9wjpJut/pOQ==[/tex]为[tex=0.643x0.786]/he/ol8BkDuTTL9yMPtH4Q==[/tex]阶零点。试证:对于充分小的[tex=2.357x1.071]zaTYmiB02c3fW3zvAQdizg==[/tex],能确定[tex=2.286x1.071]U2vn5If3wiVpiGUUuu/xGA==[/tex],使对满足[tex=4.714x1.357]KYKTcONB2QsBkF7efgqHgBb7fN8boxvZfYFDI7Xx5/U=[/tex]的[tex=0.571x0.786]HXNXn3AXpwdIpZt8+6oCEw==[/tex],函数[tex=3.071x1.357]VMKghsSNiTolxYNTkwXHOQ==[/tex]在圆[tex=4.429x1.357]BaERDnmQZjCGS/ZSW2O0X/FlFnWYVfU9+UDJKrAsXkPXV8y9mm45Ek+eHfJZzbkO[/tex]内恰有[tex=0.643x0.786]/he/ol8BkDuTTL9yMPtH4Q==[/tex]个一阶零点。
  • 举一反三