• 2022-06-19
    通过 SQL,按字母顺序选取 Actor 表中 LastName 介于 Adams 和 Carter 的所有记录的表述正确的是( )。
    A: SELECT * FROM Actor WHERE LastName BETWEEN 'Adams' AND 'Carter'
    B: SELECT * FROM Actor WHERE LastName>'Adams' AND LastName<'Carter'
    C: SELECT LastName>'Adams' AND LastName<'Carter' FROM Actor
    D: SELECT * FROM Actor WHERE LastName>'Adams' OR LastName<'Carter'
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      通过 SQL,在表 Actor 中选择 FirstName 等于 Jim 而 LastName 等于 Carter 的所有记录的表述正确的是( )。 A: SELECT * FROM Actor WHERE FirstName LIKE 'Jim' AND LastName LIKE 'Carter' B: SELECT FirstName='Jim', LastName='Carter' FROM Actor C: SELECT * FROM Actor WHERE FirstName='Jim' AND LastName='Carter' D: SELECT * FROM Actor WHERE FirstName='Jim' OR LastName='Carter'

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      通过 SQL,在表 Actor 中选择 FirstName 等于 Jim 而 LastName 等于 Carter 的所有记录的表述正确的是( )。 A: SELECT * FROM Actor WHERE FirstName LIKE 'Jim' AND LastName LIKE 'Carter' B: SELECT FirstName='Jim', LastName='Carter' FROM Actor C: SELECT * FROM Actor WHERE FirstName='Jim' AND LastName='Carter' D: SELECT * FROM Actor WHERE FirstName='Jim' OR LastName='Carter'

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      通过 SQL,在表 Actor 中选择 FirstName 等于 Jim 而 LastName 等于 Carter 的所有记录的表述正确的是( )。 A: SELECT * FROM Actor WHERE FirstName LIKE 'Jim' AND LastName LIKE 'Carter' B: SELECT FirstName='Jim', LastName='Carter' FROM Actor C: SELECT * FROM Actor WHERE FirstName='Jim' AND LastName='Carter' D: SELECT * FROM Actor WHERE FirstName='Jim' OR LastName='Carter'

    • 3

      通过 SQL,在表 Actor 中选择 FirstName 等于 Jim 而 LastName 等于 Carter 的所有记录的表述正确的是( )。 A: SELECT * FROM Actor WHERE FirstName LIKE 'Jim' AND LastName LIKE 'Carter' B: SELECT FirstName='Jim', LastName='Carter' FROM Actor C: SELECT * FROM Actor WHERE FirstName='Jim' AND LastName='Carter' D: SELECT * FROM Actor WHERE FirstName='Jim' OR LastName='Carter'

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      通过 SQL,您如何在表 Persons 中选择 FirstName 等于 Thomas ,并 且LastName 等于 Carter 的所有记录? A: SELECT * FROM Persons WHERE FirstName LIKE 'Thomas' AND LastName LIKE 'Carter' B: SELECT FirstName='Thomas', LastName='Carter' FROM Persons C: SELECT * FROM Persons WHERE FirstName='Thomas' AND LastName='Carter'