• 2022-06-08
    设A是n阶可逆方阵(n≥2),A*是A的伴随阵,则(A*)*( )
    A: |A|n-1A
    B: |A|n+1A
    C: |A|n-2A
    D: |A|n+2A
  • C

    内容

    • 0

      设\(A\)为\(n\)阶方阵,\(\left| A \right| = 2 \),则\(\left| {\left| A \right|{A^T}} \right|=\) A: \({2^{n + 1}} \) B: \({2^{n }}\) C: \({2^{n - 1}}\) D: \(2\)

    • 1

      设A是n阶矩阵,A=½E,则 |A|=( )。 A: (1/2)^n B: 2^n C: 1/2 D: 2

    • 2

      设`\n`阶方阵`\A`满足`\|A| = 2`,则`\|A^TA| = ,|A^{ - 1}| = ,| A^ ** | = ,| (A^ ** )^ ** | = ,|(A^ ** )^{ - 1} + A| = ,| A^{ - 1}(A^ ** + A^{ - 1})A| = `分别等于( ) A: \[4,\frac{1}{2},{2^{n - 1}},{2^{{{(n - 1)}^2}}},2{(\frac{3}{2})^n},\frac{{{3^n}}}{2}\] B: \[2,\frac{1}{2},{2^{n - 1}},{2^{{{(n + 1)}^2}}},2{(\frac{3}{2})^n},\frac{{{3^n}}}{2}\] C: \[4,\frac{1}{2},{2^{n + 1}},{2^{{{(n - 1)}^2}}},2{(\frac{3}{2})^{n - 1}},\frac{{{3^n}}}{2}\] D: \[2,\frac{1}{2},{2^{n - 1}},{2^{{{(n - 1)}^2}}},2{(\frac{3}{2})^{n - 1}},\frac{{{3^n}}}{2}\]

    • 3

      设\( A \) 为 \( n \)阶方阵且 \( \left| A \right| \ne 0 \),则 \( {(2A)^{ - 1}} = \)( ) A: \( {1 \over 2}{A^{ - 1}} \) B: \( {2^{n - 1}}{A^{ - 1}} \) C: \( {2^n}{A^{ - 1}} \) D: \( 2{A^{ - 1}} \)

    • 4

      若`\n`阶可逆方阵`\A`满足`\2| A | = | kA |`,`\k 大于 0`,则`\k`为 ( ) A: 2 B: \[\sqrt[n]{2}\] C: \[\sqrt 2 \] D: \[\frac{1}{{\sqrt[n]{2}}}\]