197726型轴承组装到轮对轴颈上之后，拧紧轴承端盖螺栓之力矩应符合（）的规定。 A: 216~226 B: m C: 137~147 D: m E: 157~226 F: m G: 88.2~247 H: m

交换m,n数值的方法 A: m,n=n,m B: n,m=m,n C: m,n=m,n D: n,m=n,m

【单选题】如果m>0,n<0,m<|n|,那么m,n,-m,-n的大小关系是() A. -n＞m＞-m＞n B. m＞n＞-m＞-n C. -n＞m＞n＞-m D. n＞m＞-n＞-m

197726型轴承组装到轮对轴颈上之后，拧紧轴承端盖螺栓之力矩应符合（）的规定。 A: A216~226N.m B: B137~147N.m C: C157~226N.m D: D88.2~247N.m

求给定自然数m和n的最大公约数。请完善程序。 Private Sub Command1_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r Do r = m Mod n m = n n = r Loop Until__________ Text3.Text = m End Sub Private Sub Command2_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r r = m Mod n Do Until _______ m = n n = r r = m Mod n Loop Text3.Text =____ End Sub Private Sub Command3_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r Do r = m Mod n m = n n = r Loop While________ Text3.Text =______ End Sub Private Sub Command4_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r r = m Mod n Do While______ m = n n = r r = m Mod n Loop Text3.Text =____ End Sube73f1fd63959cc8362d8c82d419c2353.png

设A与B为矩阵,AC=CB，C为m×n矩阵，则A与B分别是( )矩阵‎‏‎ A: n×m,m×n B: m×n,n×m C: n×n,m×m D: m×m,n×n

求极限[img=144x45]1803d6afb8a008a.png[/img]的MATLAB程序为：syms x m n ay=(x^m-a^m)/(x^n-a^n)limit(y,x,a)计算结果为： A: (a^(m - n)*m)/n B: a^(m - n)*m/n C: 无法求值 D: a^(m - n)*m*n E: a^(m - n)/m/n F: (a^m - n)*m)/n

定义区间（m,n）,【m,n】,（m,n】,【m,n）的长度均为n-m,其中n＞...

下面程序的功能是用“辗转相除法”求两个正整数的最大公约数。请分析程序填空。#includemain(){intr,m,n;scanf("%d%d",&m,&n);if(m A: 【1】r=m,m=n,n=r;【2】m%n; B: 【1】m%n;【2】r=m,m=n,n=r; C: 【1】r=m,m=n,n=r;【2】n%m; D: 【1】n%m;【2】r=m,m=n,n=r;

程序段： int m,n; m=15,n=12; while(m!=n) { while(m>n)m-=n; while(m 3