设 [tex=1.857x1.357]bZ4KhrFbnCaidqbMGQZfww==[/tex] 是数域 [tex=0.857x1.0]e/3JIX6pl2iXgZj/kGE1/g==[/tex] 上的多项式, 若对 [tex=0.857x1.0]e/3JIX6pl2iXgZj/kGE1/g==[/tex] 中某个非零常数 [tex=0.571x0.786]HXNXn3AXpwdIpZt8+6oCEw==[/tex], 有 [tex=5.786x1.357]O9/n04w8g0LD0HLBJ+PyLeVzFioAcsWOuRdRbXYWLZc=[/tex], 求证: [tex=1.857x1.357]bZ4KhrFbnCaidqbMGQZfww==[/tex] 必是常数多项式.

数域 [tex=0.857x1.0]e/3JIX6pl2iXgZj/kGE1/g==[/tex] 上两个 [tex=0.643x0.786]/he/ol8BkDuTTL9yMPtH4Q==[/tex] 阶反对称矩阵合同的充要条件是 A: 它们相抵 B: 它们相似 C: 作为复矩阵它们酉相似 D: ​它们的特征值相同

设[tex=0.786x1.0]kEam2pLJe4uAYVdcny2W5g==[/tex]，[tex=0.786x1.0]ri6gmnf1+J9dGqG5/1sV6A==[/tex]，[tex=0.714x1.0]9fIXCQOmrgOp2L5B47vYUQ==[/tex]三台设备工作中有两个控制要求：(1) [tex=0.786x1.0]b4HkKtHXeHofHX/gJc8Agg==[/tex]开机，则[tex=0.786x1.0]sHo1pKm+gjxjcUAJjHrarQ==[/tex]必须开机；(2) [tex=0.786x1.0]sHo1pKm+gjxjcUAJjHrarQ==[/tex]开机，则[tex=0.714x1.0]YiLkHgl7MlxE+QjUplQUKA==[/tex]也必须开机；如不满足要求，则报警装置发出报警信号[tex=0.857x1.0]e/3JIX6pl2iXgZj/kGE1/g==[/tex]。试列出符合报警要求的真值表，根据真值表写出其函数表达式并画出其逻辑门电路图。

for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是：__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1

for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是（）。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1

下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )

请仔细观察下面行列式的计算过程，如果四个等号都理解了，请选择A，否则请选择B。 | a 1 1 1 1 | |a＋4 a＋4 a＋4 a＋4 a＋4| | 1 a 1 1 1 | | 1 a 1 1 1 | | 1 1 a 1 1 |= | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 a | | 1 1 1 1 1 | | 1 a 1 1 1 | =(a＋4) | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 1 | | 0 a–1 0 0 0 | =(a＋4) | 0 0 a–1 0 0 | | 0 0 0 a–1 0 | | 0 0 0 0 a–1 | =(a＋4)(a–1)^4

共有4个站进行码分多址通信。4个站的码片序列为：a：（-1 -1 -1 +1 +1 -1 +1 +1） b：（-1 -1 +1 -1 +1 +1 +1 -1） c：（-1 +1 -1 +1 +1 +1 -1 -1） d：（-1 +1 -1 -1 -1 -1 +1 -1） 现收到这样的码片序列：（-1 +1 -3 +1 -1 -3 +1 +1），则（ ）发送1。

共有四个站进行CDMA通信，现收到这样的码片序列（-3 +1 -1 -1 +1 +1 +1 -3），则下列站点发送了数据1的是（ ） A: （-1 -1 -1 +1 +1 -1 +1 +1） B: （-1 -1 +1 -1 +1 +1 +1 -1） C: （-1 +1 -1 +1 +1 +1 -1 -1） D: （-1 +1 -1 -1 -1 -1 +1 -1）