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[tex=30.286x1.286]Ra24cNxHQ7Yav4G7aBhNUGNp82cifv65jseJqUgiLLrgS6OMv67X8zYCOqA6oZ1XuQAnLizeNZotHz9nVtpV3lSkDGHqNq0a9HlGRUvwLsha3AIkm8iwqhkNgqPuJp5pP8F6uBaETs/6Uzcil2W1xikN0u+KKXIGg7eAff/fL+c=[/tex][tex=6.5x1.286]9eYi8mPcgBFNIAji/buMZztKOuKR3dcbb5tmyOBqk/4=[/tex][img=291x130]179a6386254924c.png[/img]
下列选项为某变速器一、二、三、四挡的传动比，则三挡的传动比为（）。 A: 0.969 B: 1.286 C: 1.944 D: 3.455
下列选项为某变速器一、二、三、四挡的传动比，则三挡的传动比为（）。 A: 0.969 B: 1.286 C: 1.944 D: 3.455
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一束gong绿光以[tex=30.286x1.286]/DZgbnRjCvlwSfY2juPz++jBenOhWqgBsjnS7T65ZgOI0Lbn8KSZjmvZq/3/4ESXm8czCjkZlgi2AAG1yevHpW+NT5dYbDYIK9IZsJJY3Kr0N6nOHc0eIBzsaM5OybuZ6r5y0eEwtIGEyNOSSC13YQ==[/tex]设光轴与晶面平行, 并垂直于入射面, 试求晶体中[tex=3.929x1.286]KMPscXL1PM/GYPmtmZi5vSRd8TU9VPALX4LKlHZ/N1g=[/tex]的夹角。[tex=15.857x1.286]dNlvSbGMahSOQXqbUawGl8+DalO5BsGXY6LPgsy92ji9SfRcfUTayQkbH++3QwcEMGeqvdGmi6OqFsj+KMjRNCTUQg6rEuQfSh6MLjKWTuU=[/tex]
一束gong绿光以[tex=30.286x1.286]/DZgbnRjCvlwSfY2juPz++jBenOhWqgBsjnS7T65ZgOI0Lbn8KSZjmvZq/3/4ESXm8czCjkZlgi2AAG1yevHpW+NT5dYbDYIK9IZsJJY3Kr0N6nOHc0eIBzsaM5OybuZ6r5y0eEwtIGEyNOSSC13YQ==[/tex]设光轴与晶面平行, 并垂直于入射面, 试求晶体中[tex=3.929x1.286]KMPscXL1PM/GYPmtmZi5vSRd8TU9VPALX4LKlHZ/N1g=[/tex]的夹角。[tex=15.857x1.286]dNlvSbGMahSOQXqbUawGl8+DalO5BsGXY6LPgsy92ji9SfRcfUTayQkbH++3QwcEMGeqvdGmi6OqFsj+KMjRNCTUQg6rEuQfSh6MLjKWTuU=[/tex]
下列变量组（）是一个闭回路。 A: {x，x，x，x，x，x} B: {x，x，x，x，x} C: {x，x，x，x，x，x} D: {x，x，x，x，x，x}
下列变量组（）是一个闭回路。 A: {x，x，x，x，x，x} B: {x，x，x，x，x} C: {x，x，x，x，x，x} D: {x，x，x，x，x，x}
以下谓词蕴含式正确的是（）: (∀x) (A(x)→B(x))=>( ∀x)A(x)→(∀x)B(x)|(∀x) (A(x)↔B(x))=>( ∀x)A(x)↔(∀x)B(x)|(∀x)A(x)∨(∀x)B(x)=>( ∀x) (A(x)∨B(x))|(∃x) (A(x)∧B(x))=>(∃x)A(x)∧(∃x)B(x)
以下谓词蕴含式正确的是（）: (∀x) (A(x)→B(x))=>( ∀x)A(x)→(∀x)B(x)|(∀x) (A(x)↔B(x))=>( ∀x)A(x)↔(∀x)B(x)|(∀x)A(x)∨(∀x)B(x)=>( ∀x) (A(x)∨B(x))|(∃x) (A(x)∧B(x))=>(∃x)A(x)∧(∃x)B(x)
以下谓词蕴含式正确的是（）: (?x) (A(x)→B(x))=>( ?x)A(x)→(?x)B(x)|(?x) (A(x)?B(x))=>( ?x)A(x)?(?x)B(x)|(?x)A(x)∨(?x)B(x)=>( ?x) (A(x)∨B(x))|(?x) (A(x)∧B(x))=>(?x)A(x)∧(?x)B(x)
以下谓词蕴含式正确的是（）: (?x) (A(x)→B(x))=>( ?x)A(x)→(?x)B(x)|(?x) (A(x)?B(x))=>( ?x)A(x)?(?x)B(x)|(?x)A(x)∨(?x)B(x)=>( ?x) (A(x)∨B(x))|(?x) (A(x)∧B(x))=>(?x)A(x)∧(?x)B(x)