• 2022-07-22 问题

    设int m=200,n=10;则语句“printf("m=%d,n=%d",m,n)”的输出结果为()? A: 200,10 B: m=200,n=10 C: m=200 n=10 D: m=200n=10

    设int m=200,n=10;则语句“printf("m=%d,n=%d",m,n)”的输出结果为()? A: 200,10 B: m=200,n=10 C: m=200 n=10 D: m=200n=10

  • 2021-04-14 问题

    下面程序是求100~200的全部素数,请填空 main() { int n, i, k, m = 0; for (n = 101; n <= 200; n = n + 2) { k = sqrt(n); for (i = 2; i <= k; i++) if (n%i == 0) ; if ( ) { printf("%d ", n); m = m + 1; } if (m % 10 == 0) printf("\n"); } printf("\n"); }

    下面程序是求100~200的全部素数,请填空 main() { int n, i, k, m = 0; for (n = 101; n <= 200; n = n + 2) { k = sqrt(n); for (i = 2; i <= k; i++) if (n%i == 0) ; if ( ) { printf("%d ", n); m = m + 1; } if (m % 10 == 0) printf("\n"); } printf("\n"); }

  • 2022-06-18 问题

    一弹簧测力计的量程是10 N,刻度的总长度是5 cm,该弹簧测力计上弹簧的劲度系数是( ) A: 200 N/m B: 2 N/m C: 50 N/m D: 5 000 N/m

    一弹簧测力计的量程是10 N,刻度的总长度是5 cm,该弹簧测力计上弹簧的劲度系数是( ) A: 200 N/m B: 2 N/m C: 50 N/m D: 5 000 N/m

  • 2022-05-30 问题

    交换m,n数值的方法 A: m,n=n,m B: n,m=m,n C: m,n=m,n D: n,m=n,m

    交换m,n数值的方法 A: m,n=n,m B: n,m=m,n C: m,n=m,n D: n,m=n,m

  • 2021-04-14 问题

    【单选题】如果m>0,n<0,m<|n|,那么m,n,-m,-n的大小关系是() A. -n>m>-m>n B. m>n>-m>-n C. -n>m>n>-m D. n>m>-n>-m

    【单选题】如果m>0,n<0,m<|n|,那么m,n,-m,-n的大小关系是() A. -n>m>-m>n B. m>n>-m>-n C. -n>m>n>-m D. n>m>-n>-m

  • 2021-04-14 问题

    求给定自然数m和n的最大公约数。请完善程序。 Private Sub Command1_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r Do r = m Mod n m = n n = r Loop Until__________ Text3.Text = m End Sub Private Sub Command2_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r r = m Mod n Do Until _______ m = n n = r r = m Mod n Loop Text3.Text =____ End Sub Private Sub Command3_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r Do r = m Mod n m = n n = r Loop While________ Text3.Text =______ End Sub Private Sub Command4_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r r = m Mod n Do While______ m = n n = r r = m Mod n Loop Text3.Text =____ End Sube73f1fd63959cc8362d8c82d419c2353.png

    求给定自然数m和n的最大公约数。请完善程序。 Private Sub Command1_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r Do r = m Mod n m = n n = r Loop Until__________ Text3.Text = m End Sub Private Sub Command2_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r r = m Mod n Do Until _______ m = n n = r r = m Mod n Loop Text3.Text =____ End Sub Private Sub Command3_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r Do r = m Mod n m = n n = r Loop While________ Text3.Text =______ End Sub Private Sub Command4_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r r = m Mod n Do While______ m = n n = r r = m Mod n Loop Text3.Text =____ End Sube73f1fd63959cc8362d8c82d419c2353.png

  • 2022-06-01 问题

    设A与B为矩阵,AC=CB,C为m×n矩阵,则A与B分别是( )矩阵‎‏‎ A: n×m,m×n B: m×n,n×m C: n×n,m×m D: m×m,n×n

    设A与B为矩阵,AC=CB,C为m×n矩阵,则A与B分别是( )矩阵‎‏‎ A: n×m,m×n B: m×n,n×m C: n×n,m×m D: m×m,n×n

  • 2022-07-25 问题

    求极限[img=144x45]1803d6afb8a008a.png[/img]的MATLAB程序为:syms x m n ay=(x^m-a^m)/(x^n-a^n)limit(y,x,a)计算结果为: A: (a^(m - n)*m)/n B: a^(m - n)*m/n C: 无法求值 D: a^(m - n)*m*n E: a^(m - n)/m/n F: (a^m - n)*m)/n

    求极限[img=144x45]1803d6afb8a008a.png[/img]的MATLAB程序为:syms x m n ay=(x^m-a^m)/(x^n-a^n)limit(y,x,a)计算结果为: A: (a^(m - n)*m)/n B: a^(m - n)*m/n C: 无法求值 D: a^(m - n)*m*n E: a^(m - n)/m/n F: (a^m - n)*m)/n

  • 2022-06-19 问题

    定义区间(m,n),【m,n】,(m,n】,【m,n)的长度均为n-m,其中n>...

    定义区间(m,n),【m,n】,(m,n】,【m,n)的长度均为n-m,其中n>...

  • 2022-06-17 问题

    下面程序的功能是用“辗转相除法”求两个正整数的最大公约数。请分析程序填空。#includemain(){intr,m,n;scanf("%d%d",&m,&n);if(m A: 【1】r=m,m=n,n=r;【2】m%n; B: 【1】m%n;【2】r=m,m=n,n=r; C: 【1】r=m,m=n,n=r;【2】n%m; D: 【1】n%m;【2】r=m,m=n,n=r;

    下面程序的功能是用“辗转相除法”求两个正整数的最大公约数。请分析程序填空。#includemain(){intr,m,n;scanf("%d%d",&m,&n);if(m A: 【1】r=m,m=n,n=r;【2】m%n; B: 【1】m%n;【2】r=m,m=n,n=r; C: 【1】r=m,m=n,n=r;【2】n%m; D: 【1】n%m;【2】r=m,m=n,n=r;

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