设是来自总体X的样本,则下列哪项不是总体均值的无偏估计量 A: μ3=1/3X1+2/3X2 B: μ2=1/4X1+3/4X2 C: μ1=1/5X1+4/6X2 D: μ4=1/2X1+1/2X2
设是来自总体X的样本,则下列哪项不是总体均值的无偏估计量 A: μ3=1/3X1+2/3X2 B: μ2=1/4X1+3/4X2 C: μ1=1/5X1+4/6X2 D: μ4=1/2X1+1/2X2
求不定积分[img=115x46]17da65382f8e1b9.png[/img]; ( ) A: x - (5*log(x + 1))/4 - (3*log(x - 3)) B: (5*log(x + 1))/4 - (3*log(x - 3)) C: x - (5*log(x + 1))/4 - (3*log(x - 3))/4 D: (5*log(x + 1))/4 - (3*log(x - 3))/4
求不定积分[img=115x46]17da65382f8e1b9.png[/img]; ( ) A: x - (5*log(x + 1))/4 - (3*log(x - 3)) B: (5*log(x + 1))/4 - (3*log(x - 3)) C: x - (5*log(x + 1))/4 - (3*log(x - 3))/4 D: (5*log(x + 1))/4 - (3*log(x - 3))/4
设矩阵,已知A的特征值是λ1=2,λ2=λ3=1,则()。 A: x=-4,y=3 B: x=-4,y=-3 C: x=4,y=-3 D: x=4,y=3
设矩阵,已知A的特征值是λ1=2,λ2=λ3=1,则()。 A: x=-4,y=3 B: x=-4,y=-3 C: x=4,y=-3 D: x=4,y=3
以4,9,1为为插值节点,求\(\sqrt x \)的lagrange的插值多项式 A: \( {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) B: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) C: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x +1) + {1 \over {24}}(x - 4)(x - 9)\) D: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) - {1 \over {24}}(x - 4)(x - 9)\)
以4,9,1为为插值节点,求\(\sqrt x \)的lagrange的插值多项式 A: \( {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) B: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) C: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x +1) + {1 \over {24}}(x - 4)(x - 9)\) D: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) - {1 \over {24}}(x - 4)(x - 9)\)
阅读下面程序,则disp语句所显示结果为()。x=1;while x~=5disp(x)x=x+1;end A: 1 3 2 4 B: 1 2 3 4 C: 2 3 4 5 D: 1 3 4 2
阅读下面程序,则disp语句所显示结果为()。x=1;while x~=5disp(x)x=x+1;end A: 1 3 2 4 B: 1 2 3 4 C: 2 3 4 5 D: 1 3 4 2
设X服从[1,5]上的均匀分布,则? A: P(a≤x≤b)=(b-a)/4 B: P(3<x<6)=3/4 C: P(0<x<4)=1 D: P(-1<x<3)=1/2
设X服从[1,5]上的均匀分布,则? A: P(a≤x≤b)=(b-a)/4 B: P(3<x<6)=3/4 C: P(0<x<4)=1 D: P(-1<x<3)=1/2
(10). 已知在5重贝努里试验中成功的次数 \( X \) 满足 \( P\{X=1\}=P\{X=2\} \),则概率 \( P\{X=4\}= \)( )。 A: \(1- C_4^5 (\frac{1}{3})^4(\frac{2}{3}) \) B: \( C_5^4 (\frac{1}{3})^2(\frac{2}{3})^3 \) C: \( C_5^4 (\frac{1}{3})^4(\frac{2}{3})^4 \) D: \( C_5^4 (\frac{1}{3})^4(\frac{2}{3}) \)
(10). 已知在5重贝努里试验中成功的次数 \( X \) 满足 \( P\{X=1\}=P\{X=2\} \),则概率 \( P\{X=4\}= \)( )。 A: \(1- C_4^5 (\frac{1}{3})^4(\frac{2}{3}) \) B: \( C_5^4 (\frac{1}{3})^2(\frac{2}{3})^3 \) C: \( C_5^4 (\frac{1}{3})^4(\frac{2}{3})^4 \) D: \( C_5^4 (\frac{1}{3})^4(\frac{2}{3}) \)
设随机变量X~U(0,3),则P{1≤X<2}=()。 A: 1/3 B: 2/3 C: 1/4 D: 3/4
设随机变量X~U(0,3),则P{1≤X<2}=()。 A: 1/3 B: 2/3 C: 1/4 D: 3/4
设随机变量X的分布律为P{X=-1}=1/6, P{X=0}=1/3, P{X=1/2}=1/6, P{X=1}=1/12, P{X=2}=1/4, 则E(X²)= ( ). A: 1/3 B: 2/3 C: 31/24 D: 4/3
设随机变量X的分布律为P{X=-1}=1/6, P{X=0}=1/3, P{X=1/2}=1/6, P{X=1}=1/12, P{X=2}=1/4, 则E(X²)= ( ). A: 1/3 B: 2/3 C: 31/24 D: 4/3
设X~U(a, b), E(X)=3, D(X)=1/3, P{2<X< 3} = ( ). A: 0 B: 1/4 C: 1/3 D: 1/2
设X~U(a, b), E(X)=3, D(X)=1/3, P{2<X< 3} = ( ). A: 0 B: 1/4 C: 1/3 D: 1/2