• 2022-05-31 问题

    ‌如图所示结构,不计各构件自重和各处摩擦,若矩形平板受力偶矩为m=0.6 Nžm的力偶作用,则直角弯杆ABC对平板的约束力为( )。‌‌[img=323x224]1803c34c42e9a2e.jpg[/img]‌ A: 0.6 N B: 0.2 N C: 0.12 N D: 0.15 N

    ‌如图所示结构,不计各构件自重和各处摩擦,若矩形平板受力偶矩为m=0.6 Nžm的力偶作用,则直角弯杆ABC对平板的约束力为( )。‌‌[img=323x224]1803c34c42e9a2e.jpg[/img]‌ A: 0.6 N B: 0.2 N C: 0.12 N D: 0.15 N

  • 2022-05-30 问题

    交换m,n数值的方法 A: m,n=n,m B: n,m=m,n C: m,n=m,n D: n,m=n,m

    交换m,n数值的方法 A: m,n=n,m B: n,m=m,n C: m,n=m,n D: n,m=n,m

  • 2021-04-14 问题

    【单选题】如果m>0,n<0,m<|n|,那么m,n,-m,-n的大小关系是() A. -n>m>-m>n B. m>n>-m>-n C. -n>m>n>-m D. n>m>-n>-m

    【单选题】如果m>0,n<0,m<|n|,那么m,n,-m,-n的大小关系是() A. -n>m>-m>n B. m>n>-m>-n C. -n>m>n>-m D. n>m>-n>-m

  • 2022-06-30 问题

    流体在1.2 m×0.6 m的矩形管道内流动,其当量直径为( )。 A: 0.2 m B: 0.4 m C: 0.8 m D: 0.6 m

    流体在1.2 m×0.6 m的矩形管道内流动,其当量直径为( )。 A: 0.2 m B: 0.4 m C: 0.8 m D: 0.6 m

  • 2021-04-14 问题

    【多选题】设(X,Y)的联合分布律如下表所示,【图片】Z=X+Y,M=max(X,Y),N=min(X,Y),则以下选项正确的是 A. P ( Z =2)=0.3 B. P ( M =2)=0.6 C. P ( N =2)=0.1 D. P ( Z =2)≤0.2 E. P ( Z ≤1)≥0.5 F. P ( M =2)=0.1 G. P ( M =1)=0.4 H. P ( N =2)=0.6 I. P ( N =1)=0.5

    【多选题】设(X,Y)的联合分布律如下表所示,【图片】Z=X+Y,M=max(X,Y),N=min(X,Y),则以下选项正确的是 A. P ( Z =2)=0.3 B. P ( M =2)=0.6 C. P ( N =2)=0.1 D. P ( Z =2)≤0.2 E. P ( Z ≤1)≥0.5 F. P ( M =2)=0.1 G. P ( M =1)=0.4 H. P ( N =2)=0.6 I. P ( N =1)=0.5

  • 2021-04-14 问题

    求给定自然数m和n的最大公约数。请完善程序。 Private Sub Command1_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r Do r = m Mod n m = n n = r Loop Until__________ Text3.Text = m End Sub Private Sub Command2_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r r = m Mod n Do Until _______ m = n n = r r = m Mod n Loop Text3.Text =____ End Sub Private Sub Command3_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r Do r = m Mod n m = n n = r Loop While________ Text3.Text =______ End Sub Private Sub Command4_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r r = m Mod n Do While______ m = n n = r r = m Mod n Loop Text3.Text =____ End Sube73f1fd63959cc8362d8c82d419c2353.png

    求给定自然数m和n的最大公约数。请完善程序。 Private Sub Command1_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r Do r = m Mod n m = n n = r Loop Until__________ Text3.Text = m End Sub Private Sub Command2_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r r = m Mod n Do Until _______ m = n n = r r = m Mod n Loop Text3.Text =____ End Sub Private Sub Command3_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r Do r = m Mod n m = n n = r Loop While________ Text3.Text =______ End Sub Private Sub Command4_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r r = m Mod n Do While______ m = n n = r r = m Mod n Loop Text3.Text =____ End Sube73f1fd63959cc8362d8c82d419c2353.png

  • 2022-06-01 问题

    设A与B为矩阵,AC=CB,C为m×n矩阵,则A与B分别是( )矩阵‎‏‎ A: n×m,m×n B: m×n,n×m C: n×n,m×m D: m×m,n×n

    设A与B为矩阵,AC=CB,C为m×n矩阵,则A与B分别是( )矩阵‎‏‎ A: n×m,m×n B: m×n,n×m C: n×n,m×m D: m×m,n×n

  • 2022-07-25 问题

    求极限[img=144x45]1803d6afb8a008a.png[/img]的MATLAB程序为:syms x m n ay=(x^m-a^m)/(x^n-a^n)limit(y,x,a)计算结果为: A: (a^(m - n)*m)/n B: a^(m - n)*m/n C: 无法求值 D: a^(m - n)*m*n E: a^(m - n)/m/n F: (a^m - n)*m)/n

    求极限[img=144x45]1803d6afb8a008a.png[/img]的MATLAB程序为:syms x m n ay=(x^m-a^m)/(x^n-a^n)limit(y,x,a)计算结果为: A: (a^(m - n)*m)/n B: a^(m - n)*m/n C: 无法求值 D: a^(m - n)*m*n E: a^(m - n)/m/n F: (a^m - n)*m)/n

  • 2022-06-19 问题

    定义区间(m,n),【m,n】,(m,n】,【m,n)的长度均为n-m,其中n>...

    定义区间(m,n),【m,n】,(m,n】,【m,n)的长度均为n-m,其中n>...

  • 2022-06-17 问题

    下面程序的功能是用“辗转相除法”求两个正整数的最大公约数。请分析程序填空。#includemain(){intr,m,n;scanf("%d%d",&m,&n);if(m A: 【1】r=m,m=n,n=r;【2】m%n; B: 【1】m%n;【2】r=m,m=n,n=r; C: 【1】r=m,m=n,n=r;【2】n%m; D: 【1】n%m;【2】r=m,m=n,n=r;

    下面程序的功能是用“辗转相除法”求两个正整数的最大公约数。请分析程序填空。#includemain(){intr,m,n;scanf("%d%d",&m,&n);if(m A: 【1】r=m,m=n,n=r;【2】m%n; B: 【1】m%n;【2】r=m,m=n,n=r; C: 【1】r=m,m=n,n=r;【2】n%m; D: 【1】n%m;【2】r=m,m=n,n=r;

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