A: a=Right(Str(n),1)b=Mid(Str(n),2,1)c=Left(Str(n),1)
B: a=Right(Val(n),1)b=Mid(Val(n),2,1)c=Left(Val(n),1)
C: a=Mid(Cstr(n),3,1)b=Mid(Cstr(n),2,1)c=Mid(Cstr(n),1,1)
D: a=Mid(str(n),3,1)c=Mid(str(n),1,1)b=mid(str(n),2,1)
举一反三
- 设\( \alpha {\rm{ = }}\left( {\matrix{ 1 \cr 0 \cr 1 \cr } } \right)\;A = \alpha {\alpha ^{T,}} \) ,则\( \left| {I - {A^n}} \right| = \) ( ) A: \( 1 + {2^n} \) B: \( 1 - {2^n} \) C: \( 1 + {3^n} \) D: \( 1 - {3^n} \)
- 设$A,B$是$n$阶正交矩阵,且$\mid A\mid=-\mid B\mid$,则( ). A: $A+B$可逆 B: $A+B$不可逆 C: $\mid A+B\mid=1$ D: $\mid A+B\mid=-1$
- 打印乘法口诀的程序。 clear for m=1 to 9 for n=1 to str(m, 1)+"*"+str(n,1 )+"="+str(s,2)+"" endfor endfor return
- \( {1 \over {1 + x}} \)的麦克劳林公式为( )。 A: \( {1 \over {1 + x}} = 1 + x + { { {x^2}} \over 2} + \cdots + { { {x^n}} \over {n!}} + o\left( { { x^n}} \right) \) B: \( {1 \over {1 + x}} = 1 + x + {x^2} + \cdots + {x^n} + o\left( { { x^n}} \right) \) C: \( {1 \over {1 + x}} = 1 - x + {x^2} - \cdots + {( - 1)^n}{x^n} + o\left( { { x^n}} \right) \) D: \( {1 \over {1 + x}} = 1 - x - { { {x^2}} \over 2}- \cdots - { { {x^n}} \over {n!}} + o\left( { { x^n}} \right) \)
- 设\(A\)为\(n\)阶方阵,\(\left| A \right| = 2 \),则\(\left| {\left| A \right|{A^T}} \right|=\) A: \({2^{n + 1}} \) B: \({2^{n }}\) C: \({2^{n - 1}}\) D: \(2\)
内容
- 0
设`\n`阶方阵`\A`满足`\|A| = 2`,则`\|A^TA| = ,|A^{ - 1}| = ,| A^ ** | = ,| (A^ ** )^ ** | = ,|(A^ ** )^{ - 1} + A| = ,| A^{ - 1}(A^ ** + A^{ - 1})A| = `分别等于( ) A: \[4,\frac{1}{2},{2^{n - 1}},{2^{{{(n - 1)}^2}}},2{(\frac{3}{2})^n},\frac{{{3^n}}}{2}\] B: \[2,\frac{1}{2},{2^{n - 1}},{2^{{{(n + 1)}^2}}},2{(\frac{3}{2})^n},\frac{{{3^n}}}{2}\] C: \[4,\frac{1}{2},{2^{n + 1}},{2^{{{(n - 1)}^2}}},2{(\frac{3}{2})^{n - 1}},\frac{{{3^n}}}{2}\] D: \[2,\frac{1}{2},{2^{n - 1}},{2^{{{(n - 1)}^2}}},2{(\frac{3}{2})^{n - 1}},\frac{{{3^n}}}{2}\]
- 1
\( {1 \over {1 + x}} \)的麦克劳林公式为( ). A: \( {1 \over {1 + x}} = 1 + x + { { {x^2}} \over 2} + \cdots + { { {x^n}} \over {n!}} + o\left( { { x^n}} \right) \) B: \( {1 \over {1 + x}} = 1 + x + {x^2} + \cdots + {x^n} + o\left( { { x^n}} \right) \) C: \( {1 \over {1 + x}} = 1 - x + {x^2} - \cdots + {( - 1)^n}{x^n} + o\left( { { x^n}} \right) \)
- 2
设\( A \) 为 \( n \)阶方阵且 \( \left| A \right| \ne 0 \),则 \( {(2A)^{ - 1}} = \)( ) A: \( {1 \over 2}{A^{ - 1}} \) B: \( {2^{n - 1}}{A^{ - 1}} \) C: \( {2^n}{A^{ - 1}} \) D: \( 2{A^{ - 1}} \)
- 3
排列\( n(n - 1)(n - 2) \cdots 3 \cdot 2 \cdot 1 \)的逆序数是( ) A: \( {1 \over 2}n(n - 1) \) B: \( n(n - 1) \) C: \( n \) D: \( {n^2}(n - 1) \)
- 4
设有如下事件过程:Private Sub Command1_Click() ch = "ABCDEFG" n = Len(ch) k = 1 Do Print Mid(ch, k, 1); Mid(ch, n, 1); k = k + 1 n = n - 1 Loop Until k > nEnd Sub运行此过程所产生的输出是 A: AGBFCEDD B: AGBFCED C: GFEDCBA D: GAFBECD