Watch Part 3 of the podcast and fill in the blanks.
U4_1_1d.wmv
1. I'd like to be famous for doing something new and
.
2. Um, these days, I'd like to be famous for doing something , I think. Ah, for the, sort of charitable work.
3. Maybe being .
4. I'd like to be well-known as a graphic designer, but that's not .
5. If I were to be famous, ah, I would like to be famous or an amazing , I think, or for perhaps, a medical cure, something to cure cancer.
6. I prefer to be anonymous. I like anonymity when I'm
./js/editor20150812/dialogs/attachment_new/fileTypeImages/icon_mv.gifhttps://ucontent.cdn.unipus.cn/edx/course-v1:Unipus+nhce_3_vls_2+2017_03/resource/image/7f00fd7f2e797cebdc950268a75ee8aa2a2e6e50.jpg?imageMogr2/thumbnail/750#w=52&h=52https://ucontent.cdn.unipus.cn/edx/course-v1:Unipus+nhce_3_vls_2+2017_03/resource/image/4a9ce7bf72fc86aad5ad4061f59cd60864ae8a64.jpg?imageMogr2/thumbnail/750#w=52&h=52https://ucontent.cdn.unipus.cn/edx/course-v1:Unipus+nhce_3_vls_2+2017_03/resource/image/279fbdf59f63c8941a5618fe8b7601add8d7d4cb.jpg?imageMogr2/thumbnail/750#w=52&h=52https://ucontent.cdn.unipus.cn/edx/course-v1:Unipus+nhce_3_vls_2+2017_03/resource/image/cd0a04df42884035e1c0143391e7db2dc4475867.jpg?imageMogr2/thumbnail/750#w=52&h=52https://ucontent.cdn.unipus.cn/edx/course-v1:Unipus+nhce_3_vls_2+2017_03/resource/image/6cba129457125cca3a5e3a05c5d82be7bdc81445.jpg?imageMogr2/thumbnail/750#w=52&h=52https://ucontent.cdn.unipus.cn/edx/course-v1:Unipus+nhce_3_vls_2+2017_03/resource/image/531629fb5c6a08ca8fb81dd3753b7d689617d411.jpg?imageMogr2/thumbnail/750#w=52&h=52
U4_1_1d.wmv
1. I'd like to be famous for doing something new and
.
2. Um, these days, I'd like to be famous for doing something , I think. Ah, for the, sort of charitable work.
3. Maybe being .
4. I'd like to be well-known as a graphic designer, but that's not .
5. If I were to be famous, ah, I would like to be famous or an amazing , I think, or for perhaps, a medical cure, something to cure cancer.
6. I prefer to be anonymous. I like anonymity when I'm
./js/editor20150812/dialogs/attachment_new/fileTypeImages/icon_mv.gifhttps://ucontent.cdn.unipus.cn/edx/course-v1:Unipus+nhce_3_vls_2+2017_03/resource/image/7f00fd7f2e797cebdc950268a75ee8aa2a2e6e50.jpg?imageMogr2/thumbnail/750#w=52&h=52https://ucontent.cdn.unipus.cn/edx/course-v1:Unipus+nhce_3_vls_2+2017_03/resource/image/4a9ce7bf72fc86aad5ad4061f59cd60864ae8a64.jpg?imageMogr2/thumbnail/750#w=52&h=52https://ucontent.cdn.unipus.cn/edx/course-v1:Unipus+nhce_3_vls_2+2017_03/resource/image/279fbdf59f63c8941a5618fe8b7601add8d7d4cb.jpg?imageMogr2/thumbnail/750#w=52&h=52https://ucontent.cdn.unipus.cn/edx/course-v1:Unipus+nhce_3_vls_2+2017_03/resource/image/cd0a04df42884035e1c0143391e7db2dc4475867.jpg?imageMogr2/thumbnail/750#w=52&h=52https://ucontent.cdn.unipus.cn/edx/course-v1:Unipus+nhce_3_vls_2+2017_03/resource/image/6cba129457125cca3a5e3a05c5d82be7bdc81445.jpg?imageMogr2/thumbnail/750#w=52&h=52https://ucontent.cdn.unipus.cn/edx/course-v1:Unipus+nhce_3_vls_2+2017_03/resource/image/531629fb5c6a08ca8fb81dd3753b7d689617d411.jpg?imageMogr2/thumbnail/750#w=52&h=52
举一反三
- Put the following portions in their appropriate places in the half-finished leaflet. 1.http://course.media.unipus.cn/edx/course-v1:Unipus+efc2+2018_03/resource/image/a8e663dbb7fe27a0ca302bd999fc2dddf0f46e4d.png?imageMogr2/thumbnail/730x1319http://course.media.unipus.cn/edx/course-v1:Unipus+efc2+2018_03/resource/image/d3cc001cefc4de2cf62d8e104ce0a23d2d51526d.png?imageMogr2/thumbnail/292x288
- 以下程序的输出结果是___________。for i in range(1,11): print(i, end = " ") A: 1 2 3 4 5 6 7 8 9 B: 1 2 3 4 5 6 7 8 9 10 C: 1 2 3 4 5 D: 1 3 5 7 9
- 产生并输出如下形式的方阵。 1 2 2 2 2 2 1 3 1 2 2 2 1 4 3 3 1 2 1 4 4 3 3 3 1 4 4 4 3 3 1 5 1 4 4 3 1 5 5 5 1 4 1 5 5 5 5 5 1 #include "stdio.h" int main() { int a[7][7],i,j; for(i=0;i<7;i++) for(j=0;j<7;j++) if( (1) || i+j==6) a[i][j]=1; else if ( (2) &&i+j<6) a[i][j]=2; else if (i>j&&i+j<6) a[i][j]=3; else if (i i==j ; j==i ii i+j>6; j+i>6; 6
- 【阅读理解(选择)/完型填空】基于以下描述回答 1-2 题: 下表是 9 名评委对 10 名学生的毕业设计进行等级评定结果: 评委 A B C D E F G H I J 1 1 2 4 3 9 6 5 8 7 10 2 1 4 2 5 6 7 3 10 8 9 3 1 3 4 5 2 8 9 6 10 7 4 1 3 4 5 2 6 10 8 7 9 5 1 9 2 5 6 3 4 8 10 7 6 1 4 9 2 5 6 7 3 10 8 7 1 3 5 10 2 6 9 7 8 4 8 1 3 5 7 6 4 8 10 2 9 9 1 2 8 4 9 6 3 7 5 10
- 以下程序段实现的输出是()。for(i=0;i<;=9;i++)s[i]=i;for(i=9;i>;=0;i--)printf("%2d",s[i]);[/i][/i] A: 9 7 5 3 1 B: 1 3 5 7 9 C: 9 8 7 6 5 4 3 2 1 0 D: 0 1 2 3 4 5 6 7 8 9