• 2022-06-11
    设[tex=3.929x1.286]OgRXGBnuYUkrpNulxRW68D36NV9X5hevhTpuCfbJIg4=[/tex][tex=4.286x1.286]6c3bUDd30AE1tK5nLJwmLIKf1nPVGhR/1jwnI6n4FHE=[/tex](*),[tex=7.5x1.286]z4eHeEsob01jkxCQ0ev3xszhArEYYlGiPXUGkHYqU/4=[/tex] . 设[tex=4.5x1.286]gsdNADfoADk0WGSc+nb2CQ==[/tex]是由方程(*)所确定的隐函数,求[tex=4.0x1.286]APnhC51kScIsyBlNmslGU/pepfVCW1qfyoWKp3xsxIo=[/tex] . 
  • 举一反三