设$z = {e^{x - 2y}}$，而$x = \sin t,\;y = {t^3},$则$ { { dz} \over {dt}} = $( ) A: ${e^{\sin t - 2{t^3}}}$ B: ${e^{\sin t - 2{t^3}}}\left( {\cos t - 6{t^2}} \right)$ C: ${e^{\sin t - 2{t^3}}}\ {\sin t } $ D: ${e^{\sin t - 2{t^3}}}\,{t^3}$

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2022-06-09

设$z = {e^{x - 2y}}$，而$x = \sin t,\;y = {t^3},$则$ { { dz} \over {dt}} = $( ) A: ${e^{\sin t - 2{t^3}}}$ B: ${e^{\sin t - 2{t^3}}}\left( {\cos t - 6{t^2}} \right)$ C: ${e^{\sin t - 2{t^3}}}\ {\sin t } $ D: ${e^{\sin t - 2{t^3}}}\,{t^3}$

设$z = {e^{x - 2y}}$，而$x = \sin t,\;y = {t^3},$则$ { { dz} \over {dt}} = $( )
A: ${e^{\sin t - 2{t^3}}}$
B: ${e^{\sin t - 2{t^3}}}\left( {\cos t - 6{t^2}} \right)$
C: ${e^{\sin t - 2{t^3}}}\ {\sin t } $
D: ${e^{\sin t - 2{t^3}}}\,{t^3}$

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举一反三

设$z = {e^{x - 2y}}$，而$x = \sin t$，$y = {t^3}$，则全导数$ { { dz} \over {dt}} = $ A: ${e^{\sin t - {t^3}}}(\cos t - 6{t^2})$ B: ${e^{\sin t - 2{t^3}}}(\sin t - 6{t^2})$ C: ${e^{\cos t - 2{t^3}}}(\cos t - 6{t^2})$ D: ${e^{\sin t - 2{t^3}}}(\cos t - 6{t^2})$
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设\(z = {e^{x - 2y}}\)，而\(x = \sin t,\;y = {t^3},\)则\( { { dz} \over {dt}} = \)( ) A: \({e^{\sin t - 2{t^3}}}\) B: \({e^{\sin t - 2{t^3}}}\left( {\cos t - 6{t^2}} \right)\) C: \({e^{\sin t - 2{t^3}}}\ {\sin t } \) D: \({e^{\sin t - 2{t^3}}}\,{t^3}\)

举一反三