• 2022-06-14
    6.下列函数中$x=0$是其可去间断点的为()。
    A: $f(x) = \left\{ {\begin{array}{*{20}{c}}
    {x + \frac{1}{x},\;\;x \ne 0,} \\
    {1,\;\;\;\;\;\;\;\,x = 0} \\
    \end{array}} \right.
    $
    B: $f(x) = \left\{ {\begin{array}{*{20}{c}}
    {(1 + {x^2})\frac{1}{{{x^2}}},\;\;x \ne 0} \\
    {1,\;\;\;\;\;\;\;\;\;\quad \;\;x = 0} \\
    \end{array}} \right.
    $
    C: $f(x) = [\cos x]
    $($[\cdot]$表示取整函数)
    D: $f(x) = {\mathop{\rm sgn}} (x)
    $(符号函数)
  • 举一反三