• 2022-06-09
    已知[tex=10.286x3.929]No14tepOrgpLFcwU7iwUQXkpoWXFLxwVzHdHg8BDVo5GAGM1dLm6xRZkDfNKQaQ7hJ4kZrLrKCSq4ew4VO5DHh+KsjxR6UKsmK/1Z34hJX6y+VVKJiFRkKMHNMnaShTN[/tex],矩阵[tex=0.929x1.286]uswT/CEcOIwMpCvTz/zeaA==[/tex]满足[tex=7.643x1.286]mdLdzaMkJ0bZ1Q+PvHfNXvayLD3A1ZlECG2+4G0qDxY=[/tex],其中[tex=1.143x1.286]5WX0zEPSvFFLZ40WpRWDWQ==[/tex]是[tex=0.786x1.286]pi/GsQ3apuRt43V3XQq/tA==[/tex]的伴随矩阵,求矩阵[tex=0.929x1.286]uswT/CEcOIwMpCvTz/zeaA==[/tex]。
  • 解:由[tex=5.286x1.286]8x8Kpr1mrXtM3d85agTakxsrLu0W0bPyWwCUtqCrA4k=[/tex],用矩阵[tex=0.786x1.286]pi/GsQ3apuRt43V3XQq/tA==[/tex]左乘方程的两端,得[tex=9.357x1.286]exag2X9Dix89RmUIxaMKNt+SXP2cnapjSRgosT0glnF8bYejFCul0vnX298+JDvs[/tex][tex=8.143x1.286]O6WdBqy3TppS9E+fRr/aorXY6HMDPud+CKMNKfKsowQ=[/tex][tex=10.214x1.286]P8dPdXuM+N5BcQCKjafGhpx545DN8/fvKS9a5lkKU13+e3Dw7p+BoJNHm6AWv10/[/tex]。由于[tex=11.214x3.929]gUERekBxhLuNw+i1zjO+8+6vNVH0htlYfGwdgzLsTPodIZFsseKQnWm4DKIoRHYqAdH3PdQEowvdPmUGOweSbETpU0aPHbm1wrKBOE3j5aXdYlN4JWnr0UH2KGJtOqiv[/tex],[tex=14.143x3.929]ILTwujZrdz6pytVA81160o/qX5jedmeoBVkOeCBL7dWlWmsypIF8Xx0fgP0SzGzTbC2aGHhUErkJulnzS3aKCHr3V2Hgi2SZUukIsUifDB7i2J1sbW4PmEnlO3KfKgeC12nX6FFtLiGDwyUrxt3dpQ==[/tex],故[tex=20.357x4.143]y0HqKaejeHVmpHxQ07wV9fsXX6ruXUi3XFXy3UYUlS6qKM0hyVP6iHKw8RLvNEwRKytPLHKNxKErGJcS4ZOhLREzONgMiH3EHq++QbAhI5LRR7hMe7CF2JBLVSdImIhZVLmYnHZ0vUqCbQdYLSwo0tAHlyeMO+I9/VKIulGi8nItS4WCidzF4rmn8jlqVaX+6Qn9bfn/86G2C4mVtYq4QCH607FPR8IEZEwqG56CAlQaiZyQjwtmNywhhJBq9/Mw+7seu4CZaClVxCzrjmn+4g==[/tex]

    举一反三

    内容

    • 0

      设[tex=0.786x1.286]pi/GsQ3apuRt43V3XQq/tA==[/tex]是[tex=0.643x1.286]ZsZs11iKEvfmzDIurZth8g==[/tex]阶对称矩阵,对任意[tex=0.643x1.286]ZsZs11iKEvfmzDIurZth8g==[/tex]维列向量[tex=0.929x1.286]uswT/CEcOIwMpCvTz/zeaA==[/tex]均有[tex=4.929x1.286]C/XXYpOuqMMD92TILeWjML21tCr7xajq+PECb/HEKQA=[/tex],证明[tex=0.786x1.286]pi/GsQ3apuRt43V3XQq/tA==[/tex]是零矩阵.

    • 1

      设随机变量  [tex=0.929x1.286]uswT/CEcOIwMpCvTz/zeaA==[/tex]  服从二项分布,已知  [tex=8.857x1.286]i2Z5Uf6DCEKk3kUuqFJqMBMPcT40TtxFiK2OLjQwcas=[/tex] , 求  [tex=0.929x1.286]uswT/CEcOIwMpCvTz/zeaA==[/tex]  的分布律

    • 2

      随机观察一个总体[tex=0.929x1.286]uswT/CEcOIwMpCvTz/zeaA==[/tex],得到一个样本容量为4的样本值:[tex=6.0x1.286]/fqudzuAaVkG1raEQ4neirileu0Mcm2abu6uavBbdpc=[/tex]求[tex=0.929x1.286]uswT/CEcOIwMpCvTz/zeaA==[/tex]的经验分布函数.

    • 3

      假设[tex=0.929x1.286]uswT/CEcOIwMpCvTz/zeaA==[/tex]是[tex=0.643x1.286]ZsZs11iKEvfmzDIurZth8g==[/tex]维随机列向量,而[tex=0.786x1.286]pi/GsQ3apuRt43V3XQq/tA==[/tex]是[tex=2.643x1.286]Pcp8G3f9iSqumpymQTeO6g==[/tex]矩阵,证明:[tex=9.0x1.286]2oA4sX7FP/ySiHRnf5j+fiNGrpEdrI9ZgQDbtQSlAQOLguZgmhCwoMIEBih5Z4N1[/tex].

    • 4

      设矩阵[tex=7.786x3.5]59Kc+wt/w/lXK3ncoinsUSvqqnE0sx9/xy4ybs7JgR8WZNIBSdz4KlE4xSKjO249lQbPDS/JYeZEGELOVmTuhdZecXEf9RAwlpIEHpGHUHQx+n9l5SRui0YlU/77XxiQ[/tex],满足[tex=8.071x1.286]dfYToJ7qrutXLMZ+kuKMbpgOx2pwXdX5ask7HUgpDOI=[/tex],求矩阵[tex=0.929x1.286]uswT/CEcOIwMpCvTz/zeaA==[/tex]。