[tex=22.714x1.286]l3slMBGeTleZTGVvce5QhnXsmZhRE5HUj5HPPJvk3zpfp2daoxAPr3f1YipYwlNobqJhewEubBV+8pdoYr+5DwyLw59Oey9qWxP0KXSv4DA=[/tex]

[tex=18.286x1.286]zNinFTzSKA6stlhanIg3dwRbmNyh43BmBZIKt2EHzPSRzRwrSXyp6z8e2W2yFvqDgjOCKhBK7W6hAy6b3e/j4m4LTC9B/+/6IQlqLkk/D0w=[/tex][tex=22.714x1.286]nvXaYgezSwglNRJ3xK43aAYUBr0ZQwuhOQ7k2o7ODPyUHsqjQYUBw1PlH8uO9lmPWl55geqskBBWNlHn04+4KzGBHdaK2PXSNvEUGiYfP/o=[/tex]

下列选项为某变速器一、二、三、四挡的传动比，则三挡的传动比为（）。 A: 0.969 B: 1.286 C: 1.944 D: 3.455

[tex=39.857x1.286]hhYlGvYRiUbYK0yaMbmTM7h/uq9R/tMxeGHIKAj1sY6sgalMiEDuoEtCHkuWfmLojoibGlRBXcAMY4t9YjFGaPJmok+1CXytDUYjB+2c60I7mxt2ajFg0zAk44iIG/AJh769GhETZuQu3aqqybXchbROyoyd4l2BumZSvg4nvLEb/3mQGZiYITKJcXnzQ61U[/tex][tex=34.071x1.286]6UdGQDs3drFfd2ftc+Cs4a6ZJuuRG2BKgP2EdFGagJK+K+He5gzZ9rOS+S/NnnhYQ04BABdPYl87bKDxXXNgT+pWms2XhFktkwXX8I6jr8RWVhLLsU0pC6vT4ZJVV/q42X3pR2UwVbWc7KQeS35+SAMvE3siBtnk+l/XYV1F8Dsn7ZVDPRT+DZyj3SM7oTPA[/tex][tex=22.714x1.286]ddNU9/S+3rLVuIOn2FDOG2q8IwXu2vzw2TaTcbACxreWSB95uMmylcmTyeZT+X1cNFiF/cKDq6bUz/ebOOTjhQiQ+NK3TUHXGTkPheEy5TE=[/tex]

[tex=22.714x1.286]WLaYOJcxjHj6H1gMuFqsJN7QRj1lJlS+2pYcQnEu+4//0xqHkco7dSp4tmbls9TENCOeJVb+VhVYbDek/s/vXF3sKu1mRfWKJkrVqNDSBK0=[/tex][tex=19.429x1.286]YrquUcOKf9zzsoyV/nJvg/hYGMSo0HO0Dg8eLUoL3jlt3857RCiAxyoCJLNwZbC9Y12SrdQWFNZiw5P2eeQyavqDWLYaBa0AkFO9CryMrI8=[/tex] 未知类型：{'options': ['经肋床引流术', '胸膜内胸廓成形术', '胸膜肺切除术', '纤维板剥除术', '经胁间引流术'], 'type': 102}

下列变量组（）是一个闭回路。 A: {x，x，x，x，x，x} B: {x，x，x，x，x} C: {x，x，x，x，x，x} D: {x，x，x，x，x，x}

以下谓词蕴含式正确的是（）: (∀x) (A(x)→B(x))=>( ∀x)A(x)→(∀x)B(x)|(∀x) (A(x)↔B(x))=>( ∀x)A(x)↔(∀x)B(x)|(∀x)A(x)∨(∀x)B(x)=>( ∀x) (A(x)∨B(x))|(∃x) (A(x)∧B(x))=>(∃x)A(x)∧(∃x)B(x)

以下谓词蕴含式正确的是（）: (?x) (A(x)→B(x))=>( ?x)A(x)→(?x)B(x)|(?x) (A(x)?B(x))=>( ?x)A(x)?(?x)B(x)|(?x)A(x)∨(?x)B(x)=>( ?x) (A(x)∨B(x))|(?x) (A(x)∧B(x))=>(?x)A(x)∧(?x)B(x)

下列式中错误的是： A: (∀x)(A(x)Úp(x)) Û (∀x)A(x)Ú (∀x)p(x) B: ($x)A(x) Ù p Û ($x)(A(x) Ù p ) C: (∀x)(A(x)ÚB(x)) Þ (∀x)A(x)Ú( ∀x)B(x) D: ($x)(A(x)ÙB(x)) Þ ($x)A(x)Ù( $x)B(x)

判断下列推证是否正确。 (∀x)(A(x)→B(x))⇔(∀x)(￢A(x)∨B(x)) ⇔(∀x)￢( A(x)∧￢B(x) ) ⇔￢(∃x) ( A(x)∧￢B(x) ) ⇔￢( (∃x)A(x)∧(∃x)￢B(x) ) ⇔￢(∃x)A(x)∨￢(∃x)￢B(x) ⇔￢(∃x)A(x)∨(∀x)B(x) ⇔(∃x)A(x)→(∀x)B(x)