• 2022-11-03 问题

    [tex=25.071x1.286]+QDu8cNlXBE72bk5+/ZN7d4Tw/JLCDb+0wdc5HGrQOivW3vjYBd1YY1kosvqppPxAt0BgG9XQiqp+m+pLp8W7rFx9pjNSr7n71jtY6C5H+4wIox2R7h18ClUGdblI9rj[/tex][tex=0.0x0.0]GUJOq99/sqpSaCCchiFLqJEmsd+N+D0t25fSEdgyyH9Nwd1mAI6Nv+7Oz8FBcL096mGgzJqsanmAzn0h1mb4hzujlgIsT2rZCaOnAGgztqhX5m4g8RmQjsjbIFRa8WfUyur4O8sFUcxX+RHi67VJKQ==[/tex]

    [tex=25.071x1.286]+QDu8cNlXBE72bk5+/ZN7d4Tw/JLCDb+0wdc5HGrQOivW3vjYBd1YY1kosvqppPxAt0BgG9XQiqp+m+pLp8W7rFx9pjNSr7n71jtY6C5H+4wIox2R7h18ClUGdblI9rj[/tex][tex=0.0x0.0]GUJOq99/sqpSaCCchiFLqJEmsd+N+D0t25fSEdgyyH9Nwd1mAI6Nv+7Oz8FBcL096mGgzJqsanmAzn0h1mb4hzujlgIsT2rZCaOnAGgztqhX5m4g8RmQjsjbIFRa8WfUyur4O8sFUcxX+RHi67VJKQ==[/tex]

  • 2022-06-19 问题

    [tex=32.0x1.286]Zx6q9Eiik52bctec3DobRMoJWKlhmHJZMV8NIFWpMqxvQpPWj7Xvpy8JJuBiH4OOkUuiLxYuDuoTQ8cpDwct3LIXRI1672q3V+mi90PkvLqxokyqXTMFJ25v18q7HI9Puq4PV0XPTfB/AQMuyg8Psg==[/tex][tex=25.071x1.286]SJOFrxCdoolEctGcWq1X/cpPuHxiTNIP6ffinN8a+1u4i1vllB3KyrDiMy21k4D0Ja3Cum9hABCRhzjxZcL7t0HxkWM6et03szPejY6Cd4R+0EGBf4cMmAzEvjHpjWuB[/tex][tex=21.643x1.286]AFUbcqNDUqs1iwl/dhwwcoQ3T2j5uTCIuxGFWJVid8FdcQC8H4/pt+4yyWkgUDUZ/oY/Ezh/sz0VHcugjiHx59DUfkrD7ErirF7tBYYhvs4=[/tex]

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  • 2022-11-02 问题

    [tex=25.071x1.286]RWIo6NYZ9f3Euwg2UBNdvtLPUIEEUgR0/mcRg3fo79NNpVPbmbgkd2025SLDqvHojnFcFNcbMqLktB0fZoYsaE4TUw95kyFrWeCgMoGZTD8=[/tex] 未知类型:{'options': ['\xa0降低;\xa0', '增加;\xa0\xa0', '不变;\xa0', '\xa0不确定。'], 'type': 102}

    [tex=25.071x1.286]RWIo6NYZ9f3Euwg2UBNdvtLPUIEEUgR0/mcRg3fo79NNpVPbmbgkd2025SLDqvHojnFcFNcbMqLktB0fZoYsaE4TUw95kyFrWeCgMoGZTD8=[/tex] 未知类型:{'options': ['\xa0降低;\xa0', '增加;\xa0\xa0', '不变;\xa0', '\xa0不确定。'], 'type': 102}

  • 2022-05-29 问题

    下列选项为某变速器一、二、三、四挡的传动比,则三挡的传动比为()。 A: 0.969 B: 1.286 C: 1.944 D: 3.455

    下列选项为某变速器一、二、三、四挡的传动比,则三挡的传动比为()。 A: 0.969 B: 1.286 C: 1.944 D: 3.455

  • 2022-06-09 问题

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    [tex=42.714x1.286]ywioJPQGTzxma7SKJCI6PdYbVrIdl5+auIUIq9FLowODLvd989Xzs+zlz41cZo0Uh4nwdfC+s385RjpRMQh4Ytmu5Oh6xnicV2U9ajcUKTe5AcB3j4XniJfpj0NPuw7c5eEtr85Hgq2j6mTIrkmNj+ZFamrDMJYRXzFPD2rX56EVwQsojyfDILwzECuVNbWD[/tex][tex=25.071x1.286]C0LXb4jrNXcnt+yWArXxDZdsUPuEGB9hfO4xTgWCif82LnnpXQYo2gmKkEgAU6py3w6IrhHdx4GPBk8gVesXNrz3sTxGEMCBnWNH6lZJ+/80tEEVeaNmxgLRvJh6IkNv[/tex][tex=26.643x1.286]gr/cwcJVyT9Yd7JZro/Sjrve2EtAocO6drlYAmKCCxjwTYJmfH5ByYwAVHhIrWTnh0vO8UmDIbr7Pp5AxPL8x24u9jVSR4QRGoVIKtzlwPBDnambpYW0MZZCd+5kW62wa2vEHJCrUwTRulAYXVKAsQ==[/tex][tex=31.571x1.286]m6yCZvwxRYx3/Fx4qC0QCi+Z6BrUep5jfDpqd9As9ImODQbW10gW9d2eJqlX3/g3eKiK8WSuOgO95QNe7UToUelWtB7WouMrpGl/H+uOM91aI53aPRQspSTYzDBr2/e+NLvgi9eB+Dv4EwJzuSQSjw==[/tex]

  • 2022-06-30 问题

    下列变量组()是一个闭回路。 A: {x,x,x,x,x,x} B: {x,x,x,x,x} C: {x,x,x,x,x,x} D: {x,x,x,x,x,x}

    下列变量组()是一个闭回路。 A: {x,x,x,x,x,x} B: {x,x,x,x,x} C: {x,x,x,x,x,x} D: {x,x,x,x,x,x}

  • 2021-04-14 问题

    以下谓词蕴含式正确的是(): (∀x) (A(x)→B(x))=>( ∀x)A(x)→(∀x)B(x)|(∀x) (A(x)↔B(x))=>( ∀x)A(x)↔(∀x)B(x)|(∀x)A(x)∨(∀x)B(x)=>( ∀x) (A(x)∨B(x))|(∃x) (A(x)∧B(x))=>(∃x)A(x)∧(∃x)B(x)

    以下谓词蕴含式正确的是(): (∀x) (A(x)→B(x))=>( ∀x)A(x)→(∀x)B(x)|(∀x) (A(x)↔B(x))=>( ∀x)A(x)↔(∀x)B(x)|(∀x)A(x)∨(∀x)B(x)=>( ∀x) (A(x)∨B(x))|(∃x) (A(x)∧B(x))=>(∃x)A(x)∧(∃x)B(x)

  • 2021-04-14 问题

    以下谓词蕴含式正确的是(): (?x) (A(x)→B(x))=>( ?x)A(x)→(?x)B(x)|(?x) (A(x)?B(x))=>( ?x)A(x)?(?x)B(x)|(?x)A(x)∨(?x)B(x)=>( ?x) (A(x)∨B(x))|(?x) (A(x)∧B(x))=>(?x)A(x)∧(?x)B(x)

    以下谓词蕴含式正确的是(): (?x) (A(x)→B(x))=>( ?x)A(x)→(?x)B(x)|(?x) (A(x)?B(x))=>( ?x)A(x)?(?x)B(x)|(?x)A(x)∨(?x)B(x)=>( ?x) (A(x)∨B(x))|(?x) (A(x)∧B(x))=>(?x)A(x)∧(?x)B(x)

  • 2022-06-29 问题

    下列式中错误的是: A: (∀x)(A(x)Úp(x)) Û (∀x)A(x)Ú (∀x)p(x) B: ($x)A(x) Ù p Û ($x)(A(x) Ù p ) C: (∀x)(A(x)ÚB(x)) Þ (∀x)A(x)Ú( ∀x)B(x) D: ($x)(A(x)ÙB(x)) Þ ($x)A(x)Ù( $x)B(x)

    下列式中错误的是: A: (∀x)(A(x)Úp(x)) Û (∀x)A(x)Ú (∀x)p(x) B: ($x)A(x) Ù p Û ($x)(A(x) Ù p ) C: (∀x)(A(x)ÚB(x)) Þ (∀x)A(x)Ú( ∀x)B(x) D: ($x)(A(x)ÙB(x)) Þ ($x)A(x)Ù( $x)B(x)

  • 2022-06-25 问题

    判断下列推证是否正确。 (∀x)(A(x)→B(x))⇔(∀x)(¬A(x)∨B(x)) ⇔(∀x)¬( A(x)∧¬B(x) ) ⇔¬(∃x) ( A(x)∧¬B(x) ) ⇔¬( (∃x)A(x)∧(∃x)¬B(x) ) ⇔¬(∃x)A(x)∨¬(∃x)¬B(x) ⇔¬(∃x)A(x)∨(∀x)B(x) ⇔(∃x)A(x)→(∀x)B(x)

    判断下列推证是否正确。 (∀x)(A(x)→B(x))⇔(∀x)(¬A(x)∨B(x)) ⇔(∀x)¬( A(x)∧¬B(x) ) ⇔¬(∃x) ( A(x)∧¬B(x) ) ⇔¬( (∃x)A(x)∧(∃x)¬B(x) ) ⇔¬(∃x)A(x)∨¬(∃x)¬B(x) ⇔¬(∃x)A(x)∨(∀x)B(x) ⇔(∃x)A(x)→(∀x)B(x)

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