• 2022-05-30
    若f(x)<0成立,则g(x)≤0必须成立;若f(x)<0不成立,则g(x)无限制。引入一个0-1变量y来解决这一逻辑关系:
    A: f(x)≥-M(1-y)g(x)≤My
    B: f(x)≥-Myg(x)≤My
    C: f(x)≥-M(1-y)g(x)≤M(1-y)
    D: g(x)≥-M(1-y)f(x)≤My