写出函数[tex=3.929x1.357]7ZfQEsPDy14y6upX5JJSsQ3jB6bQ3oKU+A03sDh+dBk=[/tex]
举一反三
- 已知列表x=[3, 5, 6, 7, 9]，那么x[::-1]的结果是 A: [3, 9] B: [3, 5, 6, 7, 9] C: [3, 5, 6, 7] D: [9, 7, 6, 5, 3]
- 求函数$y = {{1 + \root 3 \of {{x^2}} - \sqrt {2x} } \over {\sqrt x }}$的导数$y' = $( ) A: $ {1 \over 2}{x^{ - {3 \over 2}}} + {1 \over 6}{x^{ - {5 \over 6}}}$ B: $ - {1 \over 2}{x^{ - {3 \over 2}}} + {1 \over 6}{x^{ - {5 \over 6}}}$ C: ${1 \over 2}{x^{ - {3 \over 2}}} - {1 \over 6}{x^{ - {5 \over 6}}}$ D: ${1 \over 3}{x^{ - {3 \over 2}}} - {1 \over 6}{x^{ - {5 \over 6}}}$
- 函数\(y = 2{x^{ - 3}}{\rm{ - }}3{x^2}\)的导数为（ ）. A: \( - 6{x^{ - 4}} - 6x\) B: \( - 6{x^{ - 4}} + 6x\) C: \( - 6{x^{ - 3}} - 6{x^3}\) D: \( - 6{x^{ - 3}} + 6{x^3}\)
- x+y=8()x-y=4()求x和y各等于几?A.()x=6()y=2()B.()x=5()y=3()C.()x=7()y=1()D.()x=3()y=5
- 函数$f(x,y,z)=x{{y}^{2}}{{z}^{3}}$在点$(1,1,1)$处的最大方向导数为 ( )． A: $14$ B: $6$ C: $\sqrt{14}$ D: $\sqrt{6}$