求极限lim(1-1/x)^kx,x趋于0,
lim(1-1/x)^kx=e^k*limxln(1-1/x),代换x=1/y,x->0时y->∞=e^k*limln(1-y)/y=e^k*lim-1/(1-y),洛必达法则=e^-k*0=e^0=1
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