• 2022-06-04
    设$L$是平面$x\cos\alpha+y\cos\beta+z\cos\gamma=1$上的闭曲线, 它所包围的区域面积为$S$, 则曲线积分$$\oint_L (z\cos\beta-y\cos\gamma)dx+(x\cos\gamma-z\cos\alpha)dy+(y\cos\alpha-x\cos\beta)dz=S,$$其中$L$依正向进行。
  • 错误

    内容

    • 0

      计算[img=127x40]1803177bfc8c3e2.png[/img]的程序表达为 A: sqrt(sin alpha ^ 2 + cos beta ^ 2) B: sqrt(sin^2(alpha) + cos^2(beta)) C: sqrt(pow(sin(alpha), 2) + pow(cos(beta), 2)) D: sqrt pow(sin(alpha), 2) + pow(cos(beta), 2)

    • 1

      设方程\({sinz} - x^2yz = 0\)确定函数\(z=z(x,y)\),则\( { { \partial z} \over {\partial x}}=\) A: \( { { 2xyz} \over {\cos z - {x^2}y}}\) B: \( { { 2xyz} \over {\cos z + {x^2}y}}\) C: \( { { xyz} \over {\cos z - {x^2}y}}\) D: \( { { 2xy} \over {\cos z - {x^2}y}}\)

    • 2

      已知\( y = \sin x + \cos x \),则 \( dy = (\cos x - \sin x)dx \)( ).

    • 3

      曲线积分$\int_{(0,0}^{(x,y)}(2x\cos y-y^2\sin x)dx+(2y\cos x-x^2\sin y)dy$与路线无关。

    • 4

      【单选题】设y=sin(cos(x)),求 结果为:(本题10.0分) A. cos(cos(x))*cos(x)+ sin(cos(x))*sin(x)^2 B. - cos(cos(x))*cos(x) - sin(cos(x))*sin(x)^2 C. - cos(cos(x))*cos(x)^2 - sin(cos(x))*sin(x)^2 D. - cos(cos(x))*cos(x) ^2- sin(cos(x))*sin(x)