设[tex=17.929x1.357]IWGfKxsrzbKlW10YkARTuE19UmzB5pq6lASvgyQ58sxwrGnlsOTbSPsb/t5CQi/DT2FNdKi4OnnqSXozdnZBCbso+k9LmsupuS2CgEhzpWpW48W0RHkLJ+IvIXnEHisC[/tex][tex=11.786x1.357]gvPGmQC/YmzkWktQggi6qrmWoQuPk0MHd8xVK52VSjQ2m6qw1b+FB3iA2sbtrKB964yCnhXyp0pqZHdnMuGhtATILqT7WWzOtejGIYHFpqY=[/tex] 求[tex=5.0x1.357]V1D753We7vezsBlKQyfrUviWb9cTk82DPTgphEp914YZzbmhaq2HORHYBx5zwar3KwWMqw6rz+boQokybz2Y/Q==[/tex]

给定一个关键码集合[tex=11.786x1.357]3hjnKKxLXQ1yZLY3w9uqI5UjpxATB0HinuB5vmSrNGk=[/tex], 假定检索各关键码的概率相 等。请画出其最佳二叉排序树。

由[tex=1.429x1.071]Y4feihE2ftsEQ+AINP64hQ==[/tex]十一烯酸[tex=11.786x1.357]WaKgiVQnt6FFP5so8Y7FJzFm8LlPo1WNMnk/N3ZmIFFoSUYp3YXoEGO5TAMetC3eAqkZHlvERbtcIrbm1VRU8D82P0P0V+8pQM8Weqb7yE4gX18NnGMbpwylndn/kkpW[/tex]合成[tex=12.571x1.357]2CAgYnOgEwM36iF0j4mVL5oqTHmab6XRnB+7FNBkIOq/AZUFzzu+2yz69dBigGfjUDJz68Tan05Sxxy3gdBETRFMnTbexRGn5peSSrHcH4IZS/2KcUjTQ/BT7Hil1P5UUW9ZpapAGasqQULbJtvOlpYW5L6CsRvQzjMLyNE+++s=[/tex]

证明:一个格是模格当且仅当对于任意的[tex=3.357x1.286]d7nh+6zcL633pRxyw0ruYHNy+uEedzAWZnTeFsYheDg=[/tex] 有[tex=11.786x1.357]MhZlk6GtRSyrpM08DsQgzzVEwZJj661HkWp+nlSR+E7C1ZzArPo2ej6YZZJMZsPDHGGkRqignEhqerwcR/0Obg==[/tex]

下列逻辑等式中不成立的有 未知类型：{'options': ['[tex=11.786x1.357]MoR0tZCOZ7sy5SffL79y5icqKCYK3wPa/vztPMH2uHs=[/tex]', '[tex=8.857x1.286]h9U2hYQzJ79ldWTMi0c6lHvV9ihfpDUg3EzuDw9SicM=[/tex]', '[tex=7.357x1.286]Otw6sbTPoQ+ytG+b0v9f8Gze5GY+XiTTfVJfWmWv734=[/tex]', '[tex=6.786x1.214]GVodKYTWEJGIlQ7avObw/RsUUV7CJP7CN8PgZiPGcFpISFNTZrjxJ3x3/HM9ysFm[/tex]'], 'type': 102}

用  [tex=0.5x0.786]C4QYj735kvdXFh+j8eTFZg==[/tex]变换求解 电阻梯形网络节点电压的差分方程[tex=11.786x1.357]gOJAJtpNjph19HDo987Gx/5mkaTuJHCyxqmy+g2BJCQ=[/tex]  其中 [tex=7.643x1.357]LWysGnCHShqHOFl0qWZsEdAsRAIMDzUDZnMPvOpixBc=[/tex](当 [tex=9.929x1.357]M/d+Ml/BC+daSmGOPDbB+4b6Q8Sec1MTRfW7o64As10WexSnevwRCUeZ4L4q82DP[/tex]

下列变量组（）是一个闭回路。 A: {x，x，x，x，x，x} B: {x，x，x，x，x} C: {x，x，x，x，x，x} D: {x，x，x，x，x，x}

以下谓词蕴含式正确的是（）: (∀x) (A(x)→B(x))=>( ∀x)A(x)→(∀x)B(x)|(∀x) (A(x)↔B(x))=>( ∀x)A(x)↔(∀x)B(x)|(∀x)A(x)∨(∀x)B(x)=>( ∀x) (A(x)∨B(x))|(∃x) (A(x)∧B(x))=>(∃x)A(x)∧(∃x)B(x)

以下谓词蕴含式正确的是（）: (?x) (A(x)→B(x))=>( ?x)A(x)→(?x)B(x)|(?x) (A(x)?B(x))=>( ?x)A(x)?(?x)B(x)|(?x)A(x)∨(?x)B(x)=>( ?x) (A(x)∨B(x))|(?x) (A(x)∧B(x))=>(?x)A(x)∧(?x)B(x)

下列式中错误的是： A: (∀x)(A(x)Úp(x)) Û (∀x)A(x)Ú (∀x)p(x) B: ($x)A(x) Ù p Û ($x)(A(x) Ù p ) C: (∀x)(A(x)ÚB(x)) Þ (∀x)A(x)Ú( ∀x)B(x) D: ($x)(A(x)ÙB(x)) Þ ($x)A(x)Ù( $x)B(x)