• 2022-06-15 问题

    求出其[tex=6.357x2.714]MhC0sa4kP8ihnFHLNuEHSwGCIA+h5VetI3byHifAbjsESmzBNb/VtMZiMVBRF39HtqMB3vftA+VxuvfGFRexPQ==[/tex]值

    求出其[tex=6.357x2.714]MhC0sa4kP8ihnFHLNuEHSwGCIA+h5VetI3byHifAbjsESmzBNb/VtMZiMVBRF39HtqMB3vftA+VxuvfGFRexPQ==[/tex]值

  • 2022-10-24 问题

    钻石的密度、折射率、色散率分别是() A: 3.52;2.417;0.044 B: 3.25;0.044;2.417 C: 3.52;2.147;0.044 D: 3.52;2.714;0.044

    钻石的密度、折射率、色散率分别是() A: 3.52;2.417;0.044 B: 3.25;0.044;2.417 C: 3.52;2.147;0.044 D: 3.52;2.714;0.044

  • 2022-06-11 问题

    写出下列反应中各步的反应类型和产物名称。[tex=16.929x1.214]gQOKNS4wI9FS1cEU236J6GaB7MxcNgMYuPj00wyM0sB+UyhpoVxEE1tZt/3nWDCSoXeFi+grVGqH6nLl+xkQpRMgOWWbstif0Q/WldWShhk=[/tex][tex=6.357x2.714]ooiZ4Ygkk84JhlWApPvT/RIZRlAmEefKANzd8V1K3OM07I4i1N4v+Uto89rjizVj[/tex]

    写出下列反应中各步的反应类型和产物名称。[tex=16.929x1.214]gQOKNS4wI9FS1cEU236J6GaB7MxcNgMYuPj00wyM0sB+UyhpoVxEE1tZt/3nWDCSoXeFi+grVGqH6nLl+xkQpRMgOWWbstif0Q/WldWShhk=[/tex][tex=6.357x2.714]ooiZ4Ygkk84JhlWApPvT/RIZRlAmEefKANzd8V1K3OM07I4i1N4v+Uto89rjizVj[/tex]

  • 2022-07-26 问题

    下面的模型是参数线性的吗?如果不是,用什么方法可以使它们成为参数线性模型?[tex=6.357x2.714]nLs7Y3+1gtJ5/RBeBMk6OzkeCdtacJSfN+OiyLanR49xEf+NiJCCJxf03aDV1eoo[/tex]

    下面的模型是参数线性的吗?如果不是,用什么方法可以使它们成为参数线性模型?[tex=6.357x2.714]nLs7Y3+1gtJ5/RBeBMk6OzkeCdtacJSfN+OiyLanR49xEf+NiJCCJxf03aDV1eoo[/tex]

  • 2022-06-14 问题

    设[tex=6.357x1.286]Hl6KOQUxBtQGuHIDH5YOE0ppGsyq9WEkBiRqjY9Lm60=[/tex]是一组样本观测值,则其标准差是 未知类型:{'options': ['[tex=8.929x3.5]R9WtSYmvBjHrvlRS/OX3Id9KBjN9VtHHS2B8TbT0+TtDhqnvGWnCFl6shZo0zglK9RD8Zd0Y6wO8Qd0dP67QDry0r9NwsQLIZ6EPocg+eLo=[/tex]', '[tex=9.143x3.5]uDjNH4vL6UOXEfgIQ9C/+OPX3aCa42Z9LyVmzyeuty+1HMvRNryoheJnA6k0OAK2ESPsBlAig3GZxj012J1Iqv2412UBqFr1rc9t2Ged8h8=[/tex]', '[tex=6.357x2.714]KbXrMEP8jmCWx3KvAIi+Wqng0eLzV0Hl6KOBnQ0LvVTbLb5tfazfem+BSDNb1Ax0jGFmFszpQC8npyfDbIcXMA==[/tex]', '[tex=5.857x2.714]KbXrMEP8jmCWx3KvAIi+WoPV2scYXnfDMfAgG0eLtj08GJ3RQgPcCJgPvJvFwt85GNBJ+PPqWT3CkrMGrGNqVA==[/tex]'], 'type': 102}

    设[tex=6.357x1.286]Hl6KOQUxBtQGuHIDH5YOE0ppGsyq9WEkBiRqjY9Lm60=[/tex]是一组样本观测值,则其标准差是 未知类型:{'options': ['[tex=8.929x3.5]R9WtSYmvBjHrvlRS/OX3Id9KBjN9VtHHS2B8TbT0+TtDhqnvGWnCFl6shZo0zglK9RD8Zd0Y6wO8Qd0dP67QDry0r9NwsQLIZ6EPocg+eLo=[/tex]', '[tex=9.143x3.5]uDjNH4vL6UOXEfgIQ9C/+OPX3aCa42Z9LyVmzyeuty+1HMvRNryoheJnA6k0OAK2ESPsBlAig3GZxj012J1Iqv2412UBqFr1rc9t2Ged8h8=[/tex]', '[tex=6.357x2.714]KbXrMEP8jmCWx3KvAIi+Wqng0eLzV0Hl6KOBnQ0LvVTbLb5tfazfem+BSDNb1Ax0jGFmFszpQC8npyfDbIcXMA==[/tex]', '[tex=5.857x2.714]KbXrMEP8jmCWx3KvAIi+WoPV2scYXnfDMfAgG0eLtj08GJ3RQgPcCJgPvJvFwt85GNBJ+PPqWT3CkrMGrGNqVA==[/tex]'], 'type': 102}

  • 2022-06-30 问题

    下列变量组()是一个闭回路。 A: {x,x,x,x,x,x} B: {x,x,x,x,x} C: {x,x,x,x,x,x} D: {x,x,x,x,x,x}

    下列变量组()是一个闭回路。 A: {x,x,x,x,x,x} B: {x,x,x,x,x} C: {x,x,x,x,x,x} D: {x,x,x,x,x,x}

  • 2021-04-14 问题

    以下谓词蕴含式正确的是(): (∀x) (A(x)→B(x))=>( ∀x)A(x)→(∀x)B(x)|(∀x) (A(x)↔B(x))=>( ∀x)A(x)↔(∀x)B(x)|(∀x)A(x)∨(∀x)B(x)=>( ∀x) (A(x)∨B(x))|(∃x) (A(x)∧B(x))=>(∃x)A(x)∧(∃x)B(x)

    以下谓词蕴含式正确的是(): (∀x) (A(x)→B(x))=>( ∀x)A(x)→(∀x)B(x)|(∀x) (A(x)↔B(x))=>( ∀x)A(x)↔(∀x)B(x)|(∀x)A(x)∨(∀x)B(x)=>( ∀x) (A(x)∨B(x))|(∃x) (A(x)∧B(x))=>(∃x)A(x)∧(∃x)B(x)

  • 2021-04-14 问题

    以下谓词蕴含式正确的是(): (?x) (A(x)→B(x))=>( ?x)A(x)→(?x)B(x)|(?x) (A(x)?B(x))=>( ?x)A(x)?(?x)B(x)|(?x)A(x)∨(?x)B(x)=>( ?x) (A(x)∨B(x))|(?x) (A(x)∧B(x))=>(?x)A(x)∧(?x)B(x)

    以下谓词蕴含式正确的是(): (?x) (A(x)→B(x))=>( ?x)A(x)→(?x)B(x)|(?x) (A(x)?B(x))=>( ?x)A(x)?(?x)B(x)|(?x)A(x)∨(?x)B(x)=>( ?x) (A(x)∨B(x))|(?x) (A(x)∧B(x))=>(?x)A(x)∧(?x)B(x)

  • 2022-06-29 问题

    下列式中错误的是: A: (∀x)(A(x)Úp(x)) Û (∀x)A(x)Ú (∀x)p(x) B: ($x)A(x) Ù p Û ($x)(A(x) Ù p ) C: (∀x)(A(x)ÚB(x)) Þ (∀x)A(x)Ú( ∀x)B(x) D: ($x)(A(x)ÙB(x)) Þ ($x)A(x)Ù( $x)B(x)

    下列式中错误的是: A: (∀x)(A(x)Úp(x)) Û (∀x)A(x)Ú (∀x)p(x) B: ($x)A(x) Ù p Û ($x)(A(x) Ù p ) C: (∀x)(A(x)ÚB(x)) Þ (∀x)A(x)Ú( ∀x)B(x) D: ($x)(A(x)ÙB(x)) Þ ($x)A(x)Ù( $x)B(x)

  • 2022-06-25 问题

    判断下列推证是否正确。 (∀x)(A(x)→B(x))⇔(∀x)(¬A(x)∨B(x)) ⇔(∀x)¬( A(x)∧¬B(x) ) ⇔¬(∃x) ( A(x)∧¬B(x) ) ⇔¬( (∃x)A(x)∧(∃x)¬B(x) ) ⇔¬(∃x)A(x)∨¬(∃x)¬B(x) ⇔¬(∃x)A(x)∨(∀x)B(x) ⇔(∃x)A(x)→(∀x)B(x)

    判断下列推证是否正确。 (∀x)(A(x)→B(x))⇔(∀x)(¬A(x)∨B(x)) ⇔(∀x)¬( A(x)∧¬B(x) ) ⇔¬(∃x) ( A(x)∧¬B(x) ) ⇔¬( (∃x)A(x)∧(∃x)¬B(x) ) ⇔¬(∃x)A(x)∨¬(∃x)¬B(x) ⇔¬(∃x)A(x)∨(∀x)B(x) ⇔(∃x)A(x)→(∀x)B(x)

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