[tex=28.286x1.286]2g86zEEOYiMLNV7DtN05uHFy+KQfedyia4tD+HXKGSNxDIEs43ZSXm4Lnavac8yhdDhmeroViTVBB5F4Tm1ePxcs0UVhBZmy6lXPyb5oxKUhihkT+0J8XWqq0mcCz8I3[/tex][tex=26.071x1.286]Rve1ROTZ6rcImc+c/OLOefMDiqh++ddlGT1OBESMbl222xWYIs2IBu7suB7DxCUIpVzzoh0uKkN4olnSBkGXQOSoEM7gcCD26FEagbhcsmbMe+cocdZEHr14kdt47+cR[/tex]

[tex=26.071x1.286]LTtqDH2vEzeo4Ywm8ePDL/wK3mlPpALgD46sMS75DfwC67t6/QmfguTKbKGKKtrg0j5E/JZce14oYL/4BIAFL0OuC5QPiI7l9nmsaha7mj3rf+abk+r3NsCI06Yxaode[/tex][tex=32.571x1.286]x1pZpDDdhjmpByDwOnZG/zAXViysSkmptYy+8j1HfXgwkkwcWEAEd2sa+bKrPG0NZUXJrX9omVOi2E/HcljHCTlcwqgy+uP8QnimsG6n28NY7n4wQ5TPpnxbYjPbr7e1t45NMGNR8kmznQu9A3i7ypR6yY/a9qn+Ch/pLh1LqU0=[/tex]

[tex=34.429x1.286]ipghJqIJZAG8ZV6c/Z0iCwAwdKPd9hos3eNWX7tYvLQTZCqn3E2dXKbhDkt0/QC3ahVHLz7I/I/oeUtt7jIdiHzzEaN3pW8qM9XzIT95iLJzwveuMYwQ8eSO4w36HmLcRJY6uRu337+7o8BdWDvY9w==[/tex][tex=26.071x1.286]8VUXXEFfvb6W1W0sRpnk7D0CaSmAZWic2G8TWv4TRTq7y8kxcLEL3Sm2BY3Zt5+Xi2ET0MknMiQ3CffK2IeWY5916tucEKLeyL35QgTtsQZaHur9LUdz2tanhVa9FdlB[/tex][tex=19.857x1.286]a9Iu9CxDa6IJztTaW51odcmX7mdM4ri0TiN1XcdV+0vZlvCJrQCfR3Nw7umnyP6rCsjZrqAlajaYsb3E9hFwSSGauOmKErK1ILCNfY1wtY8=[/tex]

下列选项为某变速器一、二、三、四挡的传动比，则三挡的传动比为（）。 A: 0.969 B: 1.286 C: 1.944 D: 3.455

[tex=26.071x1.286]Qpp+DwcA1e37QsUq5XokwDBslppvYTOf+VQ64LotmU3nrc3u7+K5rcyexD+fel1xrpvrFyClqOLgCGJ8qVPZf7UiH+ZRgKAQAFguF9GRl1chvclxNrUa6liSzjPe7Ry9[/tex] 未知类型：{'options': ['用药物控制感染', '包皮手法复位', '包皮嵌顿环切开', '包皮水肿部位切开引流', '包皮环切术'], 'type': 102}

下列变量组（）是一个闭回路。 A: {x，x，x，x，x，x} B: {x，x，x，x，x} C: {x，x，x，x，x，x} D: {x，x，x，x，x，x}

以下谓词蕴含式正确的是（）: (∀x) (A(x)→B(x))=>( ∀x)A(x)→(∀x)B(x)|(∀x) (A(x)↔B(x))=>( ∀x)A(x)↔(∀x)B(x)|(∀x)A(x)∨(∀x)B(x)=>( ∀x) (A(x)∨B(x))|(∃x) (A(x)∧B(x))=>(∃x)A(x)∧(∃x)B(x)

以下谓词蕴含式正确的是（）: (?x) (A(x)→B(x))=>( ?x)A(x)→(?x)B(x)|(?x) (A(x)?B(x))=>( ?x)A(x)?(?x)B(x)|(?x)A(x)∨(?x)B(x)=>( ?x) (A(x)∨B(x))|(?x) (A(x)∧B(x))=>(?x)A(x)∧(?x)B(x)

下列式中错误的是： A: (∀x)(A(x)Úp(x)) Û (∀x)A(x)Ú (∀x)p(x) B: ($x)A(x) Ù p Û ($x)(A(x) Ù p ) C: (∀x)(A(x)ÚB(x)) Þ (∀x)A(x)Ú( ∀x)B(x) D: ($x)(A(x)ÙB(x)) Þ ($x)A(x)Ù( $x)B(x)

判断下列推证是否正确。 (∀x)(A(x)→B(x))⇔(∀x)(￢A(x)∨B(x)) ⇔(∀x)￢( A(x)∧￢B(x) ) ⇔￢(∃x) ( A(x)∧￢B(x) ) ⇔￢( (∃x)A(x)∧(∃x)￢B(x) ) ⇔￢(∃x)A(x)∨￢(∃x)￢B(x) ⇔￢(∃x)A(x)∨(∀x)B(x) ⇔(∃x)A(x)→(∀x)B(x)