计算下列函数在指定点[tex=0.929x1.0]tstbm1OuPyfyNcfVXQkZzA==[/tex]处的微分:[tex=7.714x1.357]STgCCI4ETdGqQV9eWAQSFTlQaTDMP7KwtYh5ZIlssow=[/tex].
计算下列函数在指定点[tex=0.929x1.0]tstbm1OuPyfyNcfVXQkZzA==[/tex]处的微分:[tex=7.714x1.357]STgCCI4ETdGqQV9eWAQSFTlQaTDMP7KwtYh5ZIlssow=[/tex].
已知二元函数[tex=2.786x1.357]eWdlhSDnEKsnC2m9ymU17w==[/tex]在[tex=3.0x1.357]vwClgBOs/FToQJNjGiKg16Y3S1YqjfrJK7czLCENjaw=[/tex]处连续,证明函数[tex=4.643x1.357]OowtB6g93cJ/jt8MxYS62v8bnnHPicDlaL46dZCb/SY=[/tex]在[tex=0.929x1.0]tstbm1OuPyfyNcfVXQkZzA==[/tex]连续.
已知二元函数[tex=2.786x1.357]eWdlhSDnEKsnC2m9ymU17w==[/tex]在[tex=3.0x1.357]vwClgBOs/FToQJNjGiKg16Y3S1YqjfrJK7czLCENjaw=[/tex]处连续,证明函数[tex=4.643x1.357]OowtB6g93cJ/jt8MxYS62v8bnnHPicDlaL46dZCb/SY=[/tex]在[tex=0.929x1.0]tstbm1OuPyfyNcfVXQkZzA==[/tex]连续.
计算下列函数在指定点[tex=0.929x1.0]tstbm1OuPyfyNcfVXQkZzA==[/tex]处的微分:[tex=7.714x1.357]REScDQ0hYyzlXl6cv9G0rR0oEXRnllev9/qY/ifkprk=[/tex][tex=3.0x1.286]EM38a1zbyj31upkbG/9TlQ==[/tex][tex=0.429x1.286]iSm4rwNGwGhTQLnwM3J/Kw==[/tex].
计算下列函数在指定点[tex=0.929x1.0]tstbm1OuPyfyNcfVXQkZzA==[/tex]处的微分:[tex=7.714x1.357]REScDQ0hYyzlXl6cv9G0rR0oEXRnllev9/qY/ifkprk=[/tex][tex=3.0x1.286]EM38a1zbyj31upkbG/9TlQ==[/tex][tex=0.429x1.286]iSm4rwNGwGhTQLnwM3J/Kw==[/tex].
6.设[tex=0.5x1.214]0K9Xf7VHWdVeOrSYAKIm6Q==[/tex]为区间[tex=0.5x1.0]ycRjqHa76IDpEZtluYQxdQ==[/tex]上的单调函数,证明:若[tex=2.071x1.214]uZALtAU1binRI5TJxsGXbiEQukpWazitXMwcS5eDdtY=[/tex]为[tex=0.5x1.214]0K9Xf7VHWdVeOrSYAKIm6Q==[/tex]的间断点,则[tex=0.929x1.0]tstbm1OuPyfyNcfVXQkZzA==[/tex]必是[tex=0.5x1.214]0K9Xf7VHWdVeOrSYAKIm6Q==[/tex]的第一类间断点。
6.设[tex=0.5x1.214]0K9Xf7VHWdVeOrSYAKIm6Q==[/tex]为区间[tex=0.5x1.0]ycRjqHa76IDpEZtluYQxdQ==[/tex]上的单调函数,证明:若[tex=2.071x1.214]uZALtAU1binRI5TJxsGXbiEQukpWazitXMwcS5eDdtY=[/tex]为[tex=0.5x1.214]0K9Xf7VHWdVeOrSYAKIm6Q==[/tex]的间断点,则[tex=0.929x1.0]tstbm1OuPyfyNcfVXQkZzA==[/tex]必是[tex=0.5x1.214]0K9Xf7VHWdVeOrSYAKIm6Q==[/tex]的第一类间断点。
设[tex=1.857x1.357]Fuvm9Mwml7lIOgc0vriwJw==[/tex]在[tex=2.0x1.357]Az4ohoomfEMh5o8uh4mLdA==[/tex]上有二阶导数,且[tex=5.571x1.357]cRc5wwK9uNQf7jD/CFA6Qy8b+wQ+nVQwOXRNsr8oX1M=[/tex],又存在[tex=3.286x1.357]VxFWbZ8BTD5bADc9z8Y5XJdM38TZnkYoD7KA8ovzpeQ=[/tex]使[tex=3.571x1.357]mfamdUlkeNsEs1cZVWx/NA==[/tex].证明:在[tex=2.214x1.357]wIEaXlEuEf8SQpjP/4JuQw==[/tex]内至少存在一点[tex=0.929x1.0]tstbm1OuPyfyNcfVXQkZzA==[/tex]使[tex=4.786x1.429]o1NxfHFvh4pfuP8b7Vf/BGBk5U/OfUvDTtiYiGZF8+j0FRVqvWjPMOuRxhmgew6z[/tex].
设[tex=1.857x1.357]Fuvm9Mwml7lIOgc0vriwJw==[/tex]在[tex=2.0x1.357]Az4ohoomfEMh5o8uh4mLdA==[/tex]上有二阶导数,且[tex=5.571x1.357]cRc5wwK9uNQf7jD/CFA6Qy8b+wQ+nVQwOXRNsr8oX1M=[/tex],又存在[tex=3.286x1.357]VxFWbZ8BTD5bADc9z8Y5XJdM38TZnkYoD7KA8ovzpeQ=[/tex]使[tex=3.571x1.357]mfamdUlkeNsEs1cZVWx/NA==[/tex].证明:在[tex=2.214x1.357]wIEaXlEuEf8SQpjP/4JuQw==[/tex]内至少存在一点[tex=0.929x1.0]tstbm1OuPyfyNcfVXQkZzA==[/tex]使[tex=4.786x1.429]o1NxfHFvh4pfuP8b7Vf/BGBk5U/OfUvDTtiYiGZF8+j0FRVqvWjPMOuRxhmgew6z[/tex].
for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是:__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常
for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是:__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常
【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1
【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1
for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是()。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1
for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是()。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1
下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )
下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )
请仔细观察下面行列式的计算过程,如果四个等号都理解了,请选择A,否则请选择B。 | a 1 1 1 1 | |a+4 a+4 a+4 a+4 a+4| | 1 a 1 1 1 | | 1 a 1 1 1 | | 1 1 a 1 1 |= | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 a | | 1 1 1 1 1 | | 1 a 1 1 1 | =(a+4) | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 1 | | 0 a–1 0 0 0 | =(a+4) | 0 0 a–1 0 0 | | 0 0 0 a–1 0 | | 0 0 0 0 a–1 | =(a+4)(a–1)^4
请仔细观察下面行列式的计算过程,如果四个等号都理解了,请选择A,否则请选择B。 | a 1 1 1 1 | |a+4 a+4 a+4 a+4 a+4| | 1 a 1 1 1 | | 1 a 1 1 1 | | 1 1 a 1 1 |= | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 a | | 1 1 1 1 1 | | 1 a 1 1 1 | =(a+4) | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 1 | | 0 a–1 0 0 0 | =(a+4) | 0 0 a–1 0 0 | | 0 0 0 a–1 0 | | 0 0 0 0 a–1 | =(a+4)(a–1)^4