[tex=20.786x1.357]4WQ0Cy4+pwSf7BTU4wDloDj1z53SIwPkBoASoEh21HQnQ9ZZlrpuX5fEpDNjQ9hS1kDT9SnCPwZuWZYuMvwMy4Rd6s3zjdPdcx7QwAfKWnOIvRMlBXckCakVCPmI6FNUsf2AfLCwE+MAk275eVpJmA==[/tex], 两者相位差为[tex=1.429x1.071]YSqcTO1CWXerKNOHvWw/8g==[/tex], 对不对?

已知向量组[tex=20.786x1.357]bIFwkdlJEWwU+4V0IqE51u2bw+VARn5wbuNsgOASCDyIWXRB+74Z+pRLw5rNmdzqnAjL2GtJe//XwfFlfTULQv5bDiYEiw2XLehQM/KOPGg=[/tex]的秩为2，则t=（）（A）3（B）-3（C）2（D）-2

设R是集合A={a,b,c,d,e}上的二元关系，[tex=15.286x1.357]ZGL3KzREn/IOOOckBRdf8am5LWGchC94kkYNerFqPpFvJPRClirlM+NEv+GgY9uYcJVoWpYPYQmxxnR3boB8cdrae0Mxco97/rg8mi5uI8UX58nV/KSsDocOVgiZReDErP7x6UY+N5xo2l5AyrE/Bg==[/tex][tex=20.786x1.357]mZn9KqItxFRmvDIzfUoU1tj42hiquUkoO54P7D3IEJWuOsec/PBSG7VAaSh5Phha83mNlvnOPBw8bZB9PEgph0Ma0LRqtQCMlaTa7t9VeC/7SUAcmW/tlL9k7D4CAnoY0O5EAzgNnY7kDXZsZT8kWOID6jfqzOIK+JCD1o3ppvQG3ntc6JrSrgP7iAfTyKDtvDA5abE8TElyiQgBdoaFulUCeZOrfrS2bhIOacj2+1w=[/tex]，验证<A,R>是偏序集，并画出哈斯图。

设 [tex=6.929x1.357]oVr3Dwq4mCJpVeSnaB2gBR2XTSJNyO4yAw25WqGe74o=[/tex] 且有分解式[tex=20.786x1.357]1652UpGGMvEOgL1SSxjJOLEgin9EMF/oznTKy+MKGlDDA3FriZt39s4TY0Qvgy1GYEMggCzJnbsBlwXdFXdLr9D3G1KqcWrDVJfKqj5XJ62ajZBXHufEmh0xhTEnlHJF/XZQjSHxgEvxOxpfGDqX2Q==[/tex][tex=20.357x1.5]1ky9Y86kLwPC/LbQUpkWx2y1c2T+FOrbpbK3x5Qs2fY4DGD/GZGpedEJYTo5PfUbrMQ5M3gXdl4Kc4dKmWF7Wm32e8CNeV61rzw4W3aMMGaT4NSLMzDCyxKORgYKHZj7DmnHrgKYoXXrN1vaZgZm5rZ/CGRWLIC1ArIdpsxnoT4=[/tex]其中[tex=6.571x1.357]jClwot1xq73EO3NLCc/YZBmR8aT00sQbumrE/UTFK5Q=[/tex]是不同的首一不可约多项式.证明:[tex=22.143x1.643]09luuoNG8w24I0/TapJvEWHTDAW6rb2CByRfE9R9KHkBrMcqcGdTSx34nNdgSWQBV5EDXfhCAFoM3ZycUccObLInf2d5rBruJFwUIot94ysD7Vkdq6YnzQLtei9DzqFu4ZEAtCgnha9edroVXU5r1Frl/hKPZWGpUhf7KxzqEigOmo0hzQ3Xy9IxKfLsnjHowwbHMOd+zq5mEIHoPNrvNQ==[/tex]

下列变量组（）是一个闭回路。 A: {x，x，x，x，x，x} B: {x，x，x，x，x} C: {x，x，x，x，x，x} D: {x，x，x，x，x，x}

以下谓词蕴含式正确的是（）: (∀x) (A(x)→B(x))=>( ∀x)A(x)→(∀x)B(x)|(∀x) (A(x)↔B(x))=>( ∀x)A(x)↔(∀x)B(x)|(∀x)A(x)∨(∀x)B(x)=>( ∀x) (A(x)∨B(x))|(∃x) (A(x)∧B(x))=>(∃x)A(x)∧(∃x)B(x)

以下谓词蕴含式正确的是（）: (?x) (A(x)→B(x))=>( ?x)A(x)→(?x)B(x)|(?x) (A(x)?B(x))=>( ?x)A(x)?(?x)B(x)|(?x)A(x)∨(?x)B(x)=>( ?x) (A(x)∨B(x))|(?x) (A(x)∧B(x))=>(?x)A(x)∧(?x)B(x)

下列式中错误的是： A: (∀x)(A(x)Úp(x)) Û (∀x)A(x)Ú (∀x)p(x) B: ($x)A(x) Ù p Û ($x)(A(x) Ù p ) C: (∀x)(A(x)ÚB(x)) Þ (∀x)A(x)Ú( ∀x)B(x) D: ($x)(A(x)ÙB(x)) Þ ($x)A(x)Ù( $x)B(x)

判断下列推证是否正确。 (∀x)(A(x)→B(x))⇔(∀x)(￢A(x)∨B(x)) ⇔(∀x)￢( A(x)∧￢B(x) ) ⇔￢(∃x) ( A(x)∧￢B(x) ) ⇔￢( (∃x)A(x)∧(∃x)￢B(x) ) ⇔￢(∃x)A(x)∨￢(∃x)￢B(x) ⇔￢(∃x)A(x)∨(∀x)B(x) ⇔(∃x)A(x)→(∀x)B(x)

以下谓词公式中，( )不是逻辑有效式。 A: ($x)(P(x)∧Q(x)) Þ ($x) P(x)∧($x) Q(x) B: ("x)(P(x)∧Q(x)) Þ ("x) P(x)∧("x) Q(x) C: ($x)(P(x)∧Q(x)) Û ($x) P(x)∧($x) Q(x) D: ("x)(P(x)∧Q(x)) Û ("x) P(x)∧("x) Q(x)