[tex=5.286x3.643]Uyz5s0rmQIddjb5Jc2T/YfWlsCzhS1SWOpVVSuKllgP0STa/15Fp4j2yx5sgQ78w29bji9P0VG/fCvzPWfNyFaTkgXFLpFQTo2f307jCMu0=[/tex]

计算[tex=5.286x3.643]Uyz5s0rmQIddjb5Jc2T/YSE6dPTUH1llYx/4OLLd6aT4o2aDjoB9vRvzhoE/btWmlv6Vv8111dIY1+9AvrKouCO3KtWmWl9yz7LIbWdV1DA=[/tex]

用对角线法则求下列 3 阶行列式:[tex=5.286x3.643]TIwZYBkNsy31H1RNd/OloO8rWmj0rsClqzHoJp+hn/cy4Wiepde+pFS2tAJKm259/2aCQ71rr1RUjb/qvDoKrr93+3peeYD2iwd8cmKFdg8=[/tex]

(1)[tex=7.5x3.643]Uyz5s0rmQIddjb5Jc2T/YSWnPTWyqb60aIlQ1tDi6R94PQgscyn8dWHT8nWRVBDeJTxbZH0phE1jVq7471RIpoDOqb3B78nFOa/YZ06edWLDtOJrQjkxxTs3r+Ayqxls[/tex](2)[tex=5.286x3.643]Uyz5s0rmQIddjb5Jc2T/YUfkq0GbaA8wawpYOioNVwrgDPavIbrgY9c+V/ORVvBnw2v12s9UFmTcRBl3eSn+XP4m8jufTsuDTcgYyi3lt9U=[/tex](3)[tex=6.214x3.929]Uyz5s0rmQIddjb5Jc2T/Yd26A0JS/1yJEXxUxuChqR1yPbJIEGttJch2dNAkIS5e8YwzsJHWZfzgvnAKh9gQY8yvl9BpFwI/pzIBqU3TFCSa9ysRdwkwmyhnNxoG/Ce6[/tex]     (4)[tex=10.571x3.929]Uyz5s0rmQIddjb5Jc2T/Yd6m/Ul4M6w7nfuzR8KKgs4puZ3SmJ3tOOsdnxXja9vMjzcKgCsV348W5FVXflxgKBoNIym+EGepSUg3qnuNw4R2NNaWeWPGGVFcyHh9+ISf[/tex]

已知[tex=5.286x3.643]GzPaVdVRV8tS+M+D+HvkGmNP6ShA3Z8G8bEM7/YGIxxjoF/mnGUQxcjRNTFAX9CaT6UMzYaCojhtt6YHe++WCA==[/tex]是矩阵[tex=10.286x3.929]3BT1BgBZQ5uJXxD5dg+w2zKjdISPProdfL4sMgUUz8whb8EjL+zIuD5x5M11hWJRzut45dEcJH3kn9akSduZNmodQ19MWsjBvvCn8GbQalt7DeLdpBzAly8xSXlvcG+s[/tex]的特征向量，试确定参数[tex=1.429x1.214]rkgrF+YaaESwSQDjR6KfWg==[/tex]及特征向量[tex=0.5x1.214]Yp8n+BSB2k4l/YvG+KhxfQ==[/tex]所对应的特征值。

下列变量组（）是一个闭回路。 A: {x，x，x，x，x，x} B: {x，x，x，x，x} C: {x，x，x，x，x，x} D: {x，x，x，x，x，x}

以下谓词蕴含式正确的是（）: (∀x) (A(x)→B(x))=>( ∀x)A(x)→(∀x)B(x)|(∀x) (A(x)↔B(x))=>( ∀x)A(x)↔(∀x)B(x)|(∀x)A(x)∨(∀x)B(x)=>( ∀x) (A(x)∨B(x))|(∃x) (A(x)∧B(x))=>(∃x)A(x)∧(∃x)B(x)

以下谓词蕴含式正确的是（）: (?x) (A(x)→B(x))=>( ?x)A(x)→(?x)B(x)|(?x) (A(x)?B(x))=>( ?x)A(x)?(?x)B(x)|(?x)A(x)∨(?x)B(x)=>( ?x) (A(x)∨B(x))|(?x) (A(x)∧B(x))=>(?x)A(x)∧(?x)B(x)

下列式中错误的是： A: (∀x)(A(x)Úp(x)) Û (∀x)A(x)Ú (∀x)p(x) B: ($x)A(x) Ù p Û ($x)(A(x) Ù p ) C: (∀x)(A(x)ÚB(x)) Þ (∀x)A(x)Ú( ∀x)B(x) D: ($x)(A(x)ÙB(x)) Þ ($x)A(x)Ù( $x)B(x)

判断下列推证是否正确。 (∀x)(A(x)→B(x))⇔(∀x)(￢A(x)∨B(x)) ⇔(∀x)￢( A(x)∧￢B(x) ) ⇔￢(∃x) ( A(x)∧￢B(x) ) ⇔￢( (∃x)A(x)∧(∃x)￢B(x) ) ⇔￢(∃x)A(x)∨￢(∃x)￢B(x) ⇔￢(∃x)A(x)∨(∀x)B(x) ⇔(∃x)A(x)→(∀x)B(x)